In this problem we need to make the following addition:
2 + 8
According to this I would use the following strategy:
1. Break apart strategy:
This strategy consists in the decomposition or separation of numbers. In this way, we may break number 2 and 8 down to place value and add each, starting with the 8 or keep one number intact and only break second number down by place value and adding each place. Anyway, using this strategy we have:
2 + 8 = ?
Thus, 2 breaks into 1 plus 1 (1 + 1), 8 breaks into 4 plus 4 (4 + 4), so by associative property:
2. Explain how I decided.
The strategy of breaking apart numbers is an easy way to find additions. This strategy is amazing to add larger numbers. Therefore, we may break larger numbers up into hundreds, tens, ones, then add them.
Answer:
3 and 9
if f(x)=x^2+13 and g(x)=12x-14
Step-by-step explanation:
So when we are looking for the intersection of two functions, we are trying to figure out when they are the same. When you think same, you should think equal (=).
So we want to find when f(x)=g(x) for x.
f(x)=g(x)
Let's get everything to one side.
Subtracting 12x and adding 14 to both sides.
I'm going to reorder the left hand side and also simplify the 13+14 part:
Now since the coefficent of x^2 is just 1 our job is to find two numbers that multiply to be 27 and add up to be -12.
Those numbers are -3 and -9 since -3(-9)=27 and -3+(-9)=-12.
So the factored form of our equation is
Since the product is 0, then at least one of the factors must be 0.
So we want to solve both x-3=0 and x-9=0.
x-3=0 can be solved by adding 3 on both sides. This gives us x=3.
x-9=9 can be solved by adding 9 on both sides. This gives us x=9.
The intersection of f and g happens at x=3 or x=9.
48/3
that is 16 because
16 + 16 is 32 + 16 is 48
Hope this helps :)
Answer:
18
Step-by-step explanation:
reading from the graph HG =6 units and HI = 3 units so
A= length * with = 6*3 = 18 units²