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Hunter-Best [27]
2 years ago
15

Which of these circuits has a voltmeter?

Physics
1 answer:
sweet-ann [11.9K]2 years ago
5 0

Answer:

I think is o or mavey it could be D

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How much energy can be stored in a spring with k = 470 n/m if the maximum possible stretch is 17.0 cm ?
MrRissso [65]
The strain energy stored in a linear spring is
SE = (1/2)*k*x²
where
k =  the spring constant
x =  the extension (or compression) of the spring

Given:
k = 470 N/m
x = 17.0 cm = 0.17 m

Therefore
SE = 0.5*(470 N/m)*(0.17 m)² = 6.7915 J

Answer:  6.8 J (nearest tenth)

6 0
4 years ago
On a distance-versus-time graph, _____.
babymother [125]

Answer:

A

Explanation:

The slope of the graph has the units of vertical axis divided by horizontal axis. This means that the slope of a distance vs time graph is distance/time, or velocity.

Slope is calculated by "rise over run" so C is incorrect.

Since the slope represents velocity, a constant slope equates to a constant velocity, hence B is incorrect. Same reasoning for D being incorrect: if the slope is zero, the object is not moving.

3 0
3 years ago
The efficiency of a machine is always less than 100% because part of the energy input is used to
Travka [436]

Answer:

C. Overcome Friction

Explanation:

When using any machine usually those with moving parts, you may notice heat forming near the areas where most movement occurs. As friction continues, more energy is used up and released as heat. For that reason, the efficiency of a machine will forever be less than 100%

5 0
3 years ago
Light of wavelength 608.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 88.5 cm from the slit.
Effectus [21]

Answer:

The width of the slit is 0.167 mm

Explanation:

Wavelength of light, \lambda=608\ nm=608\times 10^{-9}\ m

Distance from screen to slit, D = 88.5 cm = 0.885 m

The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m

We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :

y=\dfrac{mD\lambda}{a}

where

a = width of the slit

a=\dfrac{mD\lambda}{y}

a=\dfrac{5\times 0.885\ m\times 608\times 10^{-9}\ m}{0.0161\ m}

a = 0.000167 m

a=1.67\times 10^{-4}\ m

a = 0.167 mm

So, the width of the slit is 0.167 mm. Hence, this is the required solution.

7 0
3 years ago
Thermal expansion means ____as the temperature
astra-53 [7]

Answer:

I believe the answer is d but I could be wrong not a 100% sure.

5 0
3 years ago
Read 2 more answers
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