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Varvara68 [4.7K]
3 years ago
15

How many oxygen atoms are found in one molecule of nitric acid, HNO3?

Physics
1 answer:
Alex17521 [72]3 years ago
5 0
In this case you have 3 Oxygen.
Consider that H is hydrogen and doesn't have a number on its side so is 1.
N is nitrogen and as well as hydrogen doesn't have a number on its side so is also 1. On the other hand, O oxygen does have a number which is 3. Which means that to make Nitric Acid you need 1 hydrogen, 1 nitrogen and 3 oxygen.
If the number where to be on the left side of the thing and <span>teh</span> start mostly <span>then</span> that would mean that there are the # atoms of nitric Acid... Hope it help :3
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A 87 kg man has a total mechanical energy of 1780 J .If he is swinging downward and is currently 1.4 m above the ground, what is
borishaifa [10]

Answer:

6.4m/s

Explanation:

The total mechanical energy of the man is 1780J.

This mechanical energy is the energy due to the motion of the body and it is a form of kinetic energy.

 Also, mass  = 87kg

   Kinetic energy  = \frac{1}{2}   m v²

m is the mass

v is the velocity

           1780  =  \frac{1}{2} x 87 x v²

                v²  = 40.9

                v  = 6.4m/s

4 0
3 years ago
28.2 km equal how many meters
gogolik [260]

Answer:exactly 28200 meters

Explanation:

6 0
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Two mugs of tea were made and their temperatures measured. Which statement correctly describes the characteristics of the partic
Cerrena [4.2K]

Answer:

Its b on ed-genuity- The particles in mug A are moving more slowly.

6 0
4 years ago
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A person pushes a 15.7-kg shopping cart at a constant velocity for a distance of 25.9 m on a flat horizontal surface. She pushes
valentinak56 [21]

Answer:

a)    F = 35.7 N, b)   W = 846.7 J, c)   W = - 846.9 J, d) W=0

Explanation:

a) For this exercise let's use Newton's second law, let's set a reference frame with the x-axis horizontally

let's break down the pushing force.

        cos (-23,7) = Fₓ / F

        sin (-237) = F_y / F

        Fₓ = F cos 23.7 = F 0.916

        F_y = F sin (-23.7) = - F 0.402

         

Y axis  

       N- W - F_y = 0

       N = W + F 0.402

X axis

       Fₓ - fr = 0

       F 0.916 = fr

       F = fr / 0.916

       F = 32.7 / 0.916

       F = 35.7 N

It is asked to calculate several jobs

b) the work of the pushing force

       W = fx x

       W = 35.7 cos 23.7 25.9

       W = 846.7 J

c) friction force work

        W = F x cos tea

friction force opposes movement

        W = - fr x

         W = - 32.7 25.9

         W = - 846.9 J

d) The work of the force would gravitate, as the displacement and the force of gravity are at 90º, the work is zero

          W = 0

6 0
3 years ago
The space shuttle edeavor is launched to altitude of 500,000 m above the surface of earth. The shuttle travels at an average rat
NikAS [45]

Answer:

714s

Explanation:

t=H/v=500000m/700m/s=714s

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3 years ago
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