A car drives a route that measures 2.75 miles.

Which solid has a volume that is three times the volume of a cone with the same base and height

anyanavicka [17]

This would be a cylinder! Hope I was helpful :)

4 0

4 years ago

Can someone please check rather or these are right or not and help me out with the rest.

bearhunter [10]

Answer:

2: AAS

4:SAS

Step-by-step explanation:

3 0

4 years ago

Which is bigger, 40% of 200 or 1/3 of 150

Rudik [331]

40% of 200...........

8 0

3 years ago

Read 2 more answers

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

fiasKO [112]

Answer:

Part 1)

a) The area is $A=36(\pi-2)\ cm^2$

b) The perimeter is $P=6(\pi+2\sqrt{2})\ cm$

Part 2)

a) The area is $A=576\ cm^2$

b) The perimeter is $P=24(\pi+2)\ cm$

Step-by-step explanation:

see the attached figure to better understand the problem

Part 1)

a) Find the area of the figure N 1

we know that

The area of the figure N 1 is equal to the area of a quarter circle minus the area of the triangle

Find the area of the quarter circle

The area of quarter circle is equal to

$A=\frac{1}{4}\pi r^{2}$

we have

$r=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}$

$A=36\pi\ cm^2$

Find the area of the triangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

we have

$b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{2}(12)(12)$

$A=72\ cm^2$

therefore

The area of the figure is

$A=(36\pi-72)\ cm^2$

Simplify

$A=36(\pi-2)\ cm^2$

b) Find the perimeter of figure N 1

we know that

The perimeter of the figure N 1 is equal to the circumference of a quarter circle plus the side AC of triangle

Find the circumference of a quarter circle

The perimeter of a quarter of circle is equal to

$C=\frac{1}{4}2\pi r$

simplify

$C=\frac{1}{2}\pi r$

we have

$r=12\ cm$

substitute

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=12^2+12^2$

$AC^2=288$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

The perimeter of the figure is

$P=(6\pi+12\sqrt{2})\ cm$

simplify

$P=6(\pi+2\sqrt{2})\ cm$

Part 2)

a) Find the area of the figure N 2

we know that

The area of the figure N 2 is equal to the area of a semicircle plus the area of a square minus the area of semicircle

so

The area of the figure is equal to the area of the square

$A=24^2\\A=576\ cm^2$

b) Find the perimeter of the figure N 2

we know that

The perimeter of the figure N 2 is equal to the length side AB plus the length side DC plus the circumference of two semicircles

so

The perimeter of the figure N 2 is equal to two times the length side AB plus the circumference of one circle

$P=2(AB)+\pi D$

$P=2(24)+\pi (24)$

$P=(48+24\pi)\ cm$

simplify

$P=24(\pi+2)\ cm$

7 0

4 years ago

Please help what is 5892.94059474 rounded to the nearest hundred

Bess [88]

Hundreds or hundredths ? i'll give you both
hundreds place : 5900.00000000
hundredths place : 5892.94000000

3 0

3 years ago

Read 2 more answers