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mash [69]
3 years ago
11

Consider the quadratic equation x? = 4x - 5. How many solutions does the equation have? A The equation has one real solution. Th

e equation has two real solutions. The equation has no real solutions. D The number of solutions cannot be determined​
Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

Answer:

{-1, 5} (two real solutions).

Step-by-step explanation:

On the left side we want x^2, not x?

We need to rewrite x? = 4x - 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:

x^2 - 4x + 5 = 0

This factors easily to (x - 5)(x + 1) = 0.

We let each factor equal zero (0) separately and solve for x:  

{-1, 5} (two real solutions).

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No. If you divide 69 by 100 you would get 0.69. If you divided 6 by 10 you would get 0.6. Therefore 69/100 and 6/10 is not equivalent.
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3 years ago
What is the quotient?<br> (-3)2<br> w<br> col- co<br> 9<br> 9<br> CO
slavikrds [6]

Answer:

The answer will be 1/9

Step-by-step explanation:

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3 0
3 years ago
!!Help!!<br>solve for x​
Murrr4er [49]

WXY = XYW ( = 41 ) ⇒  XYW is a isosceles triangle

⇒ XW = YW

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4 0
3 years ago
Slove................
m_a_m_a [10]

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Angle 3 and Angle 1 are vertical angles, meaning that they are congruent. Therefore, the measure of angle 1 is 53 degrees.

Hope this helps!

3 0
3 years ago
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Brrunno [24]

Answer:

4.3

Step-by-step explanation:

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