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mash [69]
3 years ago
11

Consider the quadratic equation x? = 4x - 5. How many solutions does the equation have? A The equation has one real solution. Th

e equation has two real solutions. The equation has no real solutions. D The number of solutions cannot be determined​
Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

Answer:

{-1, 5} (two real solutions).

Step-by-step explanation:

On the left side we want x^2, not x?

We need to rewrite x? = 4x - 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:

x^2 - 4x + 5 = 0

This factors easily to (x - 5)(x + 1) = 0.

We let each factor equal zero (0) separately and solve for x:  

{-1, 5} (two real solutions).

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Use the diagram to find the measurement of the given angle
Over [174]

Answer:

40

Step-by-step explanation:

FAC = FAE + EAD +CAD

We know FAC = 180 and CAD = 50 and EAD = 90

180 = FAE + 90 +50

Combine like terms

180 = FAE + 140

Subtract 140 from each side

180-140 = FAE +140-140

40 = FAE

6 0
3 years ago
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Whats the formula for interquartile range
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Q3-Q1=IQR is the formula.

4 0
3 years ago
Pentagon CDEFG is shown on the coordinate plane. Pentagon CDEFG is translated 7 units up and 5 units left, resulting in C'D'E'F'
Sati [7]

Answer:

The length of line segment FG is equal to the length of F'G'

The perimeter of pentagon CDEFG is equal to the perimeter of pentagon C'D'E'F'G.

Step-by-step explanation:

Given

CDEFG and C'D'E'F'G

Translation: 7 units up and 5 units left

Solving (a): Segment FG and F'G'

When a shape is translated, the resulting image will have the same lengths as the original image (i.e, translation does not change measurements)

Hence:

FG = F'G'

Solving (b): Perimeter CDEFG and C'D'EF'G'

In (a), we established that lengths do not change during translation;

Hence:

The perimeter of the CDEFG and C'D'EF'G' will remain the same

3 0
3 years ago
(1 point) Consider the function f(x)=−x3+2x2+2x+1 Find the average slope of this function on the interval (−2,6). equation edito
Whitepunk [10]

Answer:

Step-by-step explanation:

Given is a function

f(x)=-x^3+2x^2+2x+1

f(6) = -6^3+2(6^2)+2(6)+1\\=-131\\

f(-2) = -(-2)^3+2(-2)^2+2(-2)+1\\=13

Average slope of this function is change of f(x) in (-2,6)/change of x in (-2,6)

= \frac{-131-13}{8} \\=-18

By mean value theorem there exists a c such that f'(c) = -18

i.e. -3x^2+4x+2 =-8\\3x^2-4x-10 =0\\

Using quadratic formula

x = 2.61, -1.277

Out of these only 2.61 lies in the given interval

c = 2.61

7 0
4 years ago
Find the center and radius of the circle.<br> (x + 3)2 + (y + 4)2 =9
Tpy6a [65]

The general equation for any circle with its center at point (a, b) is

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So the circle in the question is centered at (-3, -4), and its radius is  3 .

7 0
3 years ago
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