All categories

2 years ago

This question is too hard

Mathematics

2 answers:

Aleonysh [2.5K]2 years ago

4 0

Answer:

7.50 is the answer to the question

olchik [2.2K]2 years ago

4 0

Answer:

$7.50 for 3 bottles of water.

Step-by-step explanation:

It is given that 4 bottles of water costs $10. Find the unit price per bottle of water, by simply dividing 4 from both the bottle of water as well as the cost:

(4 bottles of water/$10)/(4/4) = (1 bottles of water/(10/4)) = 1 bottles of water/2.5

Each bottle costs $2.50

Check. Multiply the unit price per amount of units bought:

2.50 x 4 = 10

Next, find the unit price for 3 bottles. Multiply the unit price with the amount of bottles bought:

$2.50 x 3 = $7.50

$7.50 is your answer.

You might be interested in

Mrs. Freeman is trying to determine if her new desk will fit through her classroom door. Her desk of her is 59 inches wide. She

iren [92.7K]

Answer: x = 60

Step-by-step explanation:

the equation is a^2 + b^2 = c^2.

If you draw out the problem, you plug in the information into the formula, so it would be...

x^2 + 80^2 = 100^2.

80^2 = 6,400 and 100^2 = 10,000.

x^2 + 6,400 = 10,000.

You subtract 6,400 from itself and 10,000 and then you get...

x^2 = 3,600.

You square both of those and your final answer will be x = 60.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%20%5Crm%5Csum_%7Bn%20%3D%201%7D%5E%20%5Cinfty%20%28%20-%201%20%7B%29%7D%5E%7Bn%20-%201%7D%

victus00 [196]

Let

$\displaystyle f(x) = \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)! (2n+1)}$

The exponent is indeed $2n-1$ - not a typo!

Take the antiderivative of $f$ , denoted by $F$ . This recovers a factor of $2n$ in the denominator, which lets us condense it to a single factorial.

$\displaystyle F(x) = \int f(x) \, dx = C + \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n}}{(2n+1)!}$

Recall the series expansion of sine,

$\displaystyle \sin(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}$

Then with a little algebraic manipulation, we get

$\displaystyle F(x) = \int f(x) \, dx = C + 1 - \frac{\sin(x)}x$

Differentiate to recover $f$ .

$f(x) = \dfrac{\sin(x) - x\cos(x)}{x^2}$

Finally, $f(\pi) = \frac1\pi$ , so our sum is

$\displaystyle \pi^2 f(\pi) = \sum_{n=1}^\infty (-1)^{n-1} \frac{\pi^{2n+1}}{(2n-1)! (2n+1)} = \boxed{\pi}$

3 0

1 year ago

What digit is in the hundreds period of 4,576,777

Arada [10]

7. The hundreds digit is the first digit of the final set of numbers.

4 0

3 years ago

Assume that p is a relation that contains the points (3, -4). What other point must be included in the relation if p is:1. symme

AlladinOne [14]

The point needed for the relation is $P(x,y) = (3, 4)$ if P and P' are symmetric about the x-axis.

The point needed for the relation is $P(x,y) = (-3, -4)$ if P and P' are symmetric about the y-axis.

In this exercise we are supposed to determine the coordinates of a point P under an assumption of rigid transformation. Now, we must use the following <em>symmetry</em> transformations:

Reflection about the x-axis

$S'(x,y) = S(x,y) - 2\cdot (0, s_{y})$ (1)

Reflection about the y-axis

$S'(x,y) = S(x,y) - 2\cdot (s_{x}, 0)$ (2)

Where:

$S(x,y)$ - Original point.
$S' (x,y)$ - Reflected point.
$s_{x}, s_{y}$ - Coordinates of point S.

If we know that $P'(x,y) = (3, -4)$ , the coordinates for each reflection are, respectively:

Reflection about the x-axis

$P(x,y) = (3,-4) - 2\cdot (0, -4)$

$P(x,y) = (3, 4)$

$P(x,y) = (3, 4)$ if P and P' are symmetric about the x-axis.

Reflection about the y-axis

$P(x,y) = (3, -4) - 2\cdot (3, 0)$

$P(x,y) = (-3, -4)$

$P(x,y) = (-3, -4)$ if P and P' are symmetric about the y-axis.

We kindly invite to see this question on rigid transformations: brainly.com/question/18613109

8 0

2 years ago

the camera shop wants to use the measure of central tendency expresses how successful they are in Selling cameras?which measure

Hoochie [10]

They should use "Mean" in order to calculate <span>the measure of central tendency .

In short, Your Answer would be Option A

Hope this helps!</span>

7 0

3 years ago

Read 2 more answers