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AURORKA [14]
3 years ago
5

Solve for x. Round to the nearest tenth, if necessary.

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

We need to use the sine of 17 degrees to find x. Our proportion is sin(17 degrees)=x/9.3. Multiply both sides by 9.3 and we get 9.3sin(17)=x. Using a calculator, we get about 2.7.

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A bag contains 3 red balls and 6 blue balls. 2 balls are selected at random. Find the probability of selecting 2 red balls.
Gala2k [10]

Answer: You have 1/3 possibility of grabbing 2 red balls.

Step-by-step explanation:

7 0
3 years ago
What is 6a<42 and a + 4>7
ozzi

Answer:

let's start with

6a<42

a<7

Next we simplify

a+4>7

a>7-4

a>3

Step-by-step explanation:

Answer

3<a<7

6 0
3 years ago
Help! If you know this can you tell me how to do it?
aleksandr82 [10.1K]

Answer:

c

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math.  The LCD is sin(x) cos(x).  Multiplying that in to each term looks like this:

[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?

Put everything over the common denominator now:

\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?

Since sin^2(x)+cos^2(x)=1, we will make that substitution:

\frac{1}{sin(x)cos(x)}

We could separate that fraction into 2:

\frac{1}{sin(x)}×\frac{1}{cos(x)}

\frac{1}{sin(x)}=csc(x)  and  \frac{1}{cos(x)}=sec(x)

Therefore, the simplification is

sec(x)csc(x)

5 0
4 years ago
Mr. Allen has 2 dogs, Spike and Fido. He takes both of them outside at 6:00 a.m. He takes Spike outside every 3 hours. He takes
san4es73 [151]

Answer:

3 pm

Step-by-step explanation:

Because 3x5 = 15 and 5x3=15 so it would be at 3 pm

8 0
3 years ago
Read 2 more answers
What are three equivalent ratios for 6 to 54
mariarad [96]
6:54
 
6 to 54

6/54

Those are the three ratios
4 0
4 years ago
Read 2 more answers
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