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2 years ago

A bag contains 3 red balls and 6 blue balls. 2 balls are selected at random. Find the probability of selecting 2 red balls.

Mathematics

1 answer:

Gala2k [10]2 years ago

7 0

Answer: You have 1/3 possibility of grabbing 2 red balls.

Step-by-step explanation:

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kotegsom [21]

Answer:

(a)

<u>Sample space:</u>

1*1, 1*2, 1*3, 1*4,
2*1, 2*2, 2*3, 2*4,
3*1, 3*2, 3*3, 3*4,
4*1, 4*2, 4*3, 4*4

Total 16 outcomes

(b)

(i) P(even) = 12/16 = 3/4
(ii) P(3x) = 7/16
(iii) P(perfect square) = 4/16 = 1/4

(a) <u>Sample space:</u>

1T, 1H, 2T, 2H, 3T, 3H, 4T, 4H

Total 8 outcomes

(b)

(i) 1T, 3T

P(T and odd) = 2/8 = 1/4

(ii) 1H, 4H

P(H and square) = 2/8 = 1/4

(iii) 1H, 2H, 3H, 4H

P(H) = 4/8 = 1/2

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3 years ago

Answer quick for brainliest

umka2103 [35]

Answer:

y=-1x-5

Step-by-step explanation:

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3 years ago

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larisa86 [58]

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2 years ago

Is this right? I feel like I’m wrong.

Arisa [49]

Answer:

no I believe you are correct

Hope This Helps! Have A Nice Day!!

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3 years ago

Read 2 more answers

How do I solve this?

Yuki888 [10]

The answer is B. The values of y must only be positive because it is equal to
$| - x|$
The other options states that the values of y could be negative which is why it is wrong.

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3 years ago