Answer:
a² + b² = 68
a3 + b3 = 520
Step-by-step explanation:
Given :
a + b = 10 (1)
ab = 16 (2)
A. Find a² + b²
(a + b)² = a² + 2ab + b² (3)
Substitutite the values of (1) and (2) into (3)
(10)² = a² + 2(16) + b²
100 = a² + 32 + b²
Subtract 32 from both sides
100 - 32 = a² + b²
a² + b² = 68
B. a^3 + b^3
(a + b)^3 = a^3 + b^3 + 3ab(a + b)
(10)^3 = a^3 + b^3 + 3*16(10)
1000 = a^3 + b^3 + 480
a^3 + b^3 = 1000 - 480
a3 + b3 = 520
Since x=-3y+5, substitute x for -3y+5.
2(-3y+5)+8y=4
Distribute.
-6y+10+8y= 4
2y+10= 4
Subtract 10 on both sides.
2y=-6
Divide by 2.
y=-3
Plug in y=-3.
x=-3(-3)+5
x= 9+5
x=14
(14,-3)
We can check this.
2(14)+8(-3)=4
28-24=4
4=4 <== this works
I hope this helps!
~kaikers
Answer:age of the man: 75 age of the woman:25
Step-by-step explanation:
First, We need to define the variables
x: age of the man
y: age of the woman
at the first time he has three times her age
x=3y (1)
in 25 years time
(x+25)=2(y+25) (2)
we clear the equation
X+25=2y+50
X=2y+25
we substitute in the (1) equation:
2y+25=3y
y=25
x=3*25=75
Answer:
10/9 or 1.1 repeating
Step-by-step explanation:
Use formula y2-y1/x2-x1.
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