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GarryVolchara [31]
3 years ago
11

Algebra 1 :

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

What we have been given here are two points.

f(3) = -4 is the same as (3, -4)

f(2) = 6 is the same as (2, 6)

We can then use these two points to find the equation of a line.

Step 1: Find the slope

Slope Formula: (y2 - y1) / (x2 - x1)

Slope = (6 - - 4) / (2 - 3) = (10) / (-1) = -10

Step 2: Find the y-intercept

To find the y-intercept, we'll take our slope and one of our points and plug them into slope-intercept form, then solve for b.

Slope-Intercept Form: y = mx + b

Point = (2, 6)

6 = 2(-10) + b

6 = -20 + b

b = 26

Step 3: Create the equation of the line

Now that we have the slope and y-intercept, all that's left to do is plug both of those values into slope-intercept form.

y = -10x + 26

Answer: y = -10x + 26

Hope this helps!

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<h3>Postulates and Theorems</h3>

A postulate is a statement that is assumed true without proof. A theorem is a true statement that can be proven. Listed below are six postulates and the theorems that can be proven from these postulates.

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Postulate 2: A plane contains at least three noncollinear points.

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Postulate 6: If two planes intersect, then their intersection is a line.

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Theorem 2: If a point lies outside a line, then exactly one plane contains both the line and the point.

Theorem 3: If two lines intersect, then exactly one plane contains both lines.

Example 1: State the postulate or theorem you would use to justify the statement made about each figure.

(a)

Through any three noncollinear points, there is exactly one plane (Postulate 4).

(b)

Through any two points, there is exactly one line (Postulate 3).

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(d)

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(g)

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Step-by-step explanation:

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