Its a 2.2 chance that your group orders meat toppings because the chances of probability get lower as each person chooses and multiplying all three probabilities you get 2.2
Answer:
The answer is below
Step-by-step explanation:
Let s(t) represent the amount of salt in the tank at time t. Therefore:
ds / dt = (rate of salt flowing into the tank) - (rate of salt going out of the tank)
![\frac{ds}{dt}=[(0.08\ kg/L*6\ L/min)+(0.09\ kg/L*5\ L/min)]-(\frac{s\ kg}{1000\ L}*11\ L/min ) \\\\\frac{ds}{dt}=(0.48\ kg/min+0.45\ kg/min)-(\frac{11s}{1000}\ kg/min )\\\\\frac{ds}{dt}=0.93\ kg/min-\frac{11s}{1000}\ kg/min \\\\\frac{ds}{dt}=\frac{930-11s}{1000}\ kg/min \\\\\frac{ds}{930-11s}=\frac{1}{1000}dt\\\\Integrating:\\\\\int\limits { \frac{ds}{930-11s}} \, ds=\int\limits {\frac{1}{1000}} \, dt\\\\-\frac{1}{11}ln(930-11s)=\frac{t}{1000}+C\\\\multiply\ through\ by\ -11:](https://tex.z-dn.net/?f=%5Cfrac%7Bds%7D%7Bdt%7D%3D%5B%280.08%5C%20kg%2FL%2A6%5C%20L%2Fmin%29%2B%280.09%5C%20kg%2FL%2A5%5C%20L%2Fmin%29%5D-%28%5Cfrac%7Bs%5C%20kg%7D%7B1000%5C%20L%7D%2A11%5C%20L%2Fmin%20%29%20%5C%5C%5C%5C%5Cfrac%7Bds%7D%7Bdt%7D%3D%280.48%5C%20kg%2Fmin%2B0.45%5C%20kg%2Fmin%29-%28%5Cfrac%7B11s%7D%7B1000%7D%5C%20kg%2Fmin%20%29%5C%5C%5C%5C%5Cfrac%7Bds%7D%7Bdt%7D%3D0.93%5C%20kg%2Fmin-%5Cfrac%7B11s%7D%7B1000%7D%5C%20kg%2Fmin%20%5C%5C%5C%5C%5Cfrac%7Bds%7D%7Bdt%7D%3D%5Cfrac%7B930-11s%7D%7B1000%7D%5C%20kg%2Fmin%20%5C%5C%5C%5C%5Cfrac%7Bds%7D%7B930-11s%7D%3D%5Cfrac%7B1%7D%7B1000%7Ddt%5C%5C%5C%5CIntegrating%3A%5C%5C%5C%5C%5Cint%5Climits%20%7B%20%5Cfrac%7Bds%7D%7B930-11s%7D%7D%20%5C%2C%20ds%3D%5Cint%5Climits%20%7B%5Cfrac%7B1%7D%7B1000%7D%7D%20%5C%2C%20%20dt%5C%5C%5C%5C-%5Cfrac%7B1%7D%7B11%7Dln%28930-11s%29%3D%5Cfrac%7Bt%7D%7B1000%7D%2BC%5C%5C%5C%5Cmultiply%5C%20through%5C%20by%5C%20-11%3A)
The half life of the value of the computer is = 2 years
The time it will take for the computer to be worth 10% of its purchase price= 3.5 years.
<h3>Calculation of the half-life of computer</h3>
V = value of computer= $2000
t = time after original purchase = 1 year
h = half-life of the value of the computer
The half-life value can be calculated using the given formula;
V(t) = 2000(1/2)^t/h
2000×1 = (2000×1/2)^1/h
2000= 1000^1/h
Make h the subject formula,
h= 2000/1000
h = 2 years
The time it will take for the computer to become 10% of its purchase price is,
10/100×2000
= 20000/100
=$200
If after 1 year the computer= $1516
This means that in a year the price of the computer reduces by approximately $500
Therefore it will take approximately 3.5 years to purchase the computer at 10% it's organic price.
Learn more about percentage here:
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computer
Given:
mean, μ = 11 lb
Std. deviation, σ = 2.1
Let x = the weight that separates the top 5% of the crop.
The z-score is
z = (x - μ)/σ
= (x - 11)/2.1
From standard z-table for normal distribution,
P(z=1.645) = 0.95
Therefore
(x - 11)/2.1 = 1.645
x - 11 = 1.645/2.1 = 0.7833
x = 11.783
Answer: 11.8 lb (nearest tenth)
Answer:
I believe the answer is $246
Step-by-step explanation:
