Question

Write a function in vertex form that is translated 3 units down and 3 units to the right of f (x) = x^2

Answer 1

Answer:

f(x)= (x-3)^2-3

Step-by-step explanation:

Vertex Form: y= a(x-h)^2+k

a is the reflection

h and k are the vertex so in an ordered pair (x,y) = (h,k)

Since it is translating 3 units down it is going to be a negative 3.  If it was translating up it would be positive 3.  This represents the "k" because it is moving on the y-axis.

Since it is translating 3 units to the right it is going to be positive 3.  If it was translating left it would be negative 3. This represents the "h" because it is moving on the x-axis.

After plugging it into the vertex form formula: f(x)= (x-3)^2-3

*notice when I plugged the "h" in it became negative because x-(3)= x-3*