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Alborosie
4 years ago
7

Please help me if you can. It would be amazing

Mathematics
1 answer:
Serhud [2]4 years ago
7 0
Your answer is A, since point A is 5 units away from the y-axis.
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Question 8 (1 point)<br> Find the perimeter of the triangle.
Romashka [77]

Answer:

D

Step-by-step explanation:

its the closest to the answer i got so that must be it

6 0
2 years ago
уA 5-digit PIN number is selected. What it the probability that there are no repeated digits?hoThe probability that no numbers a
Ber [7]

Since there are 5 choices and there are 10 possible digits for each digit of the PIN( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9)

The total value possible 5 pins are 10⁵ = 100000

Using permutation, since 5 numbers are selected without repetition:

\frac{n!}{(n-k)!}=\frac{10!}{(10-5)!}=30240

The probability that no numbers are repeated is= 30240/ 100000

≈ 0.302

3 0
1 year ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20%
zhuklara [117]

Answer:

a. 5% of the employees will experience lost-time accidents in both years

b. 24% of the employees will suffer at least one lost-time accident over the two-year period

Step-by-step explanation:

a. What percentage of the employees will experience lost-time accidents in both years?

20% last year, of those who suffered last year, 25% during this year. So

p = 0.2*0.25 = 0.05

5% of the employees will experience lost-time accidents in both years.

b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?

5% during the two years.

10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.

So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.

First year yes, not on the second.

75% of 20%. So, total:

0.05 + 0.05*0.8 + 0.75*0.2 = 0.24

24% of the employees will suffer at least one lost-time accident over the two-year period

3 0
3 years ago
Please assist me with this math problem​
Paha777 [63]

Answer:  see below

<u>Step-by-step explanation:</u>

I'm not sure exactly what you are asking for but here is what the box plot tells you:

Minimum is 17 items.

Q1 (Lower Quartile) is 22 items. So, 25% of the customers bought 22 items.

Q2 (Median) is 32 items. So, 50% of the customers bought 32 items.

Q3 (Upper Quartile) is 35 items, So, 75% of the customers bought 35 items.

Maximum is 62 items.

The data is "heavier" on the right so it is skewed left.

Range is 62 - 17 = 45

IQR (Interquartile range) is Q3 - Q1 = 35 - 22 = 13

6 0
4 years ago
What is the value of m
zhuklara [117]

Answer:

x=16\frac{2}{3}

Step-by-step explanation:

Since the rectangles are similar, that means that corresponding sides are proportional. Therefore, the ratio of similitude is 5/3 (GH and CD are corresponding sides and the ratio between their lengths is 5/3). If the ratio of similitude is 5/3 and two corresponding sides are m and 10, then we can make an equation:

\frac{m}{10}=\frac{5}{3}

Cross-multiply to get:

3m=50

Thus, m = \frac{50}{3} which is 16\frac{2}{3} .

Hope this helps :)

8 0
2 years ago
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