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Mandarinka [93]
3 years ago
15

I need help with this question really badly please help.

Mathematics
1 answer:
Dahasolnce [82]3 years ago
3 0
D: of ;;;9d 38383 valise irl for 1
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NEED HELP FAST WILL MARK BRAINLIEST
lawyer [7]

Answer:

B

Step-by-step explanation:

B) because both result in the equation 8 x = 400, which simplifies to x = 50

<em>Hope this helps</em>

<em>-Amelia</em>

5 0
4 years ago
The size 4 soccer ball Sean’s team uses should weigh no more than 0.37 kilograms, and no less than 0.31 kilograms. A soccer bag
dmitriy555 [2]

Answers:

Q: What is the most they could weigh together?

A:  0.74 kg

-----

Q: What is the least they could weigh together?

A:  0.62 kg

=================================================

Work Shown:

x = weight of first ball

y = weight of second ball

each ball has a weight range of 0.31 kg to 0.37 kg, so,

0.31 \le x \le 0.37

0.31 \le y \le 0.37

add straight down to get

0.31+0.31 \le x+y \le 0.37+0.37

which simplifies to

0.62 \le x+y \le 0.74

the two soccer balls have a weight range of 0.62 to 0.74, inclusive of both endpoints.

--------

Without using algebra, you basically just add the smallest the two weights could be (0.31) to itself to get 0.31+0.31 = 0.62 which represents the smallest the two weights combined can be. The same happens with the largest weight of 0.37 to get 0.37+0.37 = 0.74 as the max weight of both objects together.

7 0
4 years ago
After going trick-or-treating, Cheyan is trying to
Mice21 [21]

Answer:

16

Step-by-step explanation:

All you have to do is add 14+34 which is 48. Since you know that she averaged 3 pieces of candy you have to divide 48 and 3 which is 16

3 0
3 years ago
Read 2 more answers
lfador produces gear for a racquetball league. It costs him S0.005 per square centimeter to racquetballs for the league. In the
kotegsom [21]

Answer:

out estimation is underestimate when we increase the cost.

Step-by-step explanation:

Given diameter of the racquetballs (x)= 4 cm

New diameter = 4.05 cm

Therefore, change in diameter ( Δ x) = 0.05.

Cost Function of x diameter of 30,000 racquetballs at the rate 0.005 per square centimeter

C(x) = 30000 × 0.005 × S/4

C(x) = 150 × S/4 = 37.5 × S.

We are given S = π r^2

Therefore,

C(x)= 37.5 π r^2.

C(4) = 37.5 *π*(4)^2 = 37.5 π*16

C (4+0.05) = 37.5 *π*(4.05)^2 = 37.5 * π * 16.4025.

Finding first derivative of cost function, we get

C'(x) = 2 * 37.5 * π r = 75 π r

C(4) = 75 * π * 4 = 300 π

We know,

Δ C(x)/ Δ x = C'(x).

Plugging value of Δ x and x

Δ C(4) = Δ x * C '(4) = 0.05 * 300 π = 15 π = 15 * 3.141 = 47.12.

We also know

Δ C(x) = C(x+Δx) - C(x) = (37.5 * π * 16.4025) - (37.5 π*16) = 37.5 π (16.4025 -16)

                            = 37.5 π(0.4025)

                            = 37.5 * 3.14 * 0.4025

                            = 47.42.

We can see that 47.42 is greater than 47.12.

Therefore, out estimation is underestimate when we increase the cost.

4 0
4 years ago
M and N are complementary angles, fill in the<br> blank Sin M = 12/19, Cos N
yKpoI14uk [10]

Answer:

12/19

Step-by-step explanation:

M and are complementary then

sinM=cosN

Given: sinM=12/19

cosN=12/19

8 0
3 years ago
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