All 4 sides of a square are the same length.
If the perimeter of the square is 20-ft, then each side is 20-ft/4 = 5 ft.
If you increase the length of the square by 2-ft, then its new length is 5+2 = 7-ft.
If you decrease the width of the square by 1-ft, then its new width is 5-1 = 4-ft.
The area of the new figure is (length) x (width) = (7-ft x 4-ft) = <u>28 square feet</u>.
Given parameters:
Actual length = 260m
Drawing length = 286mm
Unknown:
Scale used = ?
Solution:
A scale compares drawing length to ground distance;
To find the scale,
Express the two quantities in the same unit;
actual length = 260 x 10⁻³m = 0.26mm
Now;
drawing length : actual length
286mm : 260 x 10⁻³mm
divide by 286;
1mm on drawing : 9 x 10⁻⁴mm on map
or;
1mm on drawing is 0.9m on ground
This question actually states 2930 divided by 5
We use this method by first seeing how was fives go into the first number
In this case no 5's go into 2 so we put a 0 above the line and carry over the 2 to the 9.
Out number now says 29, 5 fives gointo 29with a remainder of 4.
We write the 5 above the line and carry the four across.
We now have 43, 8 fives gointo 43 with a remainder of 3.
We write the 8 above the line and carry the 3.
Our last number now says 30, 6 fives gointo 30 exactly so we can just write 6 above the line.
The numbers we have writen across the top now say 586 which is the answer to this problem.
So u Line them up like the photo then you multiply 2 x 4 = 8 and multiply 3 x 1 = 3 so you get 8/3 then simply 8/3 the answer is 2 2/3
