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Naya [18.7K]
2 years ago
7

Find area round to nearest hundredth

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
6 0

Answer:

area = 693

Step-by-step explanation:

The area of a quadrilateral can be found using the formula; base * height

It is given that the height is 33, the base is 21;

Multiply the two

21 *33 = 693

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A coin sorting machine can sort a certain number of coins in 15 min a second machine can sort the same number of coins in 30 min
padilas [110]

Answer:

10 minutes

Step-by-step explanation:

Let's use the variable x for the amount of coins.

The first machine can sort x coins in 15 minutes, so its speed is x/15 coins/minute.

The second machine can sort x coins in 30 minutes, so its speed is x/30 coins/minute.

If we sum the speeds, we have that the speed will be:

speed = (x/15) + (x/30) = (2x + x)/30 = 3x/30 = x/10

The total speed can sort x/10 coins per minute, that is x coins in 10 minutes.

7 0
3 years ago
37.5% 1/3 25% and 3/10 least to greatest
barxatty [35]
25% 3/10 1/3 and 37.5%

.25,.30,.33,.375
7 0
2 years ago
What's the answer to this? Or how do I figure it out?
trapecia [35]
B.) 14/43 
1&2 =7+7
= 14
Bottam:
14 + 8 +6 + 9 +6
= 43
Lastly
= 14/43

6 0
2 years ago
Need to solve for Y by filling in the blanks<br>(y +44)°, 86, (3y)°​
lapo4ka [179]
Answer:

1.89

Solution:

We have -44x - 86 = -3

First, we move the non x terms to the RHS of the equation. To do this, we add 86 to both sides.

Note: if a = b, then a + c = b + c
Therefore, -44x - 86 + 86 = -3 + 86

or, -44x = 83

Next, divide both sides by -44, which is the coefficent of x

Note: if a = b, then a ÷ c = b ÷ c
-44x
-44
=
83
-44

or, x = -1.89


Explaination:

This is right I guess
4 0
2 years ago
Which of the values from the set (-7, -6, -2, 0, 1, 3) satisfy the inequality-5x + 5&lt; 25
Troyanec [42]

Answer: -2, 0, 1, 3

Step-by-step explanation:

when you multiply -7 and -6 by -5 than add 5 you get a higher number than 25.

when you multiply -2, 0, 1 And 3 by -5 than add 5 you get a lower number than 25.

4 0
2 years ago
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