Answer:
7 is the answer
Step-by-step explanation:
hope this helps
Answer:
a) and d) are bijections. b) and c) are not
Step-by-step explanation:
a) Every linear non constant function is a bijection. We can easily find the inverse of f by making a simple calculus.
If y is on the function image, we have y = -3x + 4 for certain x, then
y- 4 = -3x
-(y-4)/3 = x
therefore ![f^{-1}(x) = -(x-4)/3](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20-%28x-4%29%2F3%20)
b) -3 * X² + 4 is not a bijection because quadratic funtions arent bijective. If you evaluate in opposite values you will obtain the same result. For example f(-1) = f(1) = 6
c) (x+1)/(x+2) is not a bijection. It isnt even defined in -2 because the denominator is equal to 0 if X= -2 and we cant divide by 0. A bijective function from R to R must be defined in every element of R. In general, homographic non linear functions are not bijective for the same reason this function is not.
d)
is bijective. There isnt a simple argument we can use to conclude this. We have no other choice than trying to find the inverse function by making a calculus.
Y = ![X^5+1](https://tex.z-dn.net/?f=%20X%5E5%2B1%20)
Y-1 = ![X^5](https://tex.z-dn.net/?f=%20X%5E5)
![(Y-1)^{1/5} = X](https://tex.z-dn.net/?f=%20%28Y-1%29%5E%7B1%2F5%7D%20%3D%20X%20)
Not that since 5 is odd, we can calculate
independently of which value Y-1 takes. Therefore
, and we can conclude that f is bijective.
I hope this helps you!
Answer:
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Step-by-step explanation:
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Answer:
B/2
Step-by-step explanation:
Jeez better not get this wrong... anyway, to start off the total is 19 books. Adding 5 then adding 3, She returned 8 books to the 19 she checked out. Uhhhh no clear answer.
NOT the first one cause 8 isn't the total. Don't think it would be the last one cause that's no fun. So it's either the second or the third one. The third one also makes no sense cause it only includes the returns from yesterday. I'm going with the second one
Answer:
Step-by-step explanation:
Given: The radius is 6 cm
To find the area + circumference we need to use 2 formulas:
Area: pi* radius^2
Circumference: 2*pi*r
First we can do the area
I will use "pi" for pi instead of 3.14
pi * 6^2
= 36 pi
The area is 36 pi
Next, circumference
2 * pi *r
2*pi*6
= 12 pi
So the area is 36 pi, and the circumference is 12 pi