Each number in the sum is even, so we can remove a factor of 2.
2 + 4 + 6 + 8 + ... + 78 + 80 = 2 (1 + 2 + 3 + 4 + ... + 39 + 40)
Use whatever technique you used in (a) and (b) to compute the sum
1 + 2 + 3 + 4 + ... + 39 + 40
With Gauss's method, for instance, we have
S = 1 + 2 + 3 + ... + 38 + 39 + 40
S = 40 + 39 + 38 + ... + 3 + 2 + 1
2S = (1 + 40) + (2 + 39) + ... + (39 + 2) + (40 + 1) = 40×41
S = 20×21 = 420
Then the sum you want is 2×420 = 840.
Hi,
Answer: (x+5)^2
<u>My work:</u> For this problem can be easily achieved by factoring your terms. To do this you figure out what can go into 10x and 25 which is 5. From the there you take x^2 and 10x and see what can take out which would be x. Your answer would be (x + 5)^2 or (x +5) (x + 5). This can be done in 2 easy steps!
<u><em>Numerical work:</em></u>
1.x^2 10x +25
Before this step figure out what goes into you equation.
2. (X + 5)^2 or (X+5) (X + 5)
Answer:
4
Step-by-step explanation:
16/4
Answer:
I think the answer is

Step-by-step explanation:
Reason :

Therefore
