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2 years ago

Can someone help me please

Mathematics

1 answer:

HACTEHA [7]2 years ago

8 0

first add the ratio numbers which is 12

$\frac{2}{12} \times 6000 = 1000$

then divide 1000 with 175

=5.71

5.71×2.25

=12.85 ruro

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3 years ago

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999,765 rounded to the nearest hundred thousand

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3 years ago

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Irving can I remember the correct order of the five digits on his ID number he does remember that the ID number contains the dig

Cloud [144]

Answer: $\frac{27}{125}$

Step-by-step explanation:

Here the total numbers are 1, 4, 3, 7, 6

Since the total number of possible arrangement = $5\times 5 \times5 \times 5 \times 5=5^5$

The total number of the odd numbers in the given numbers = 3

Thus the possible arrangement that the first three digits will be odd numbers = $3\times 3\times 3\times 5\times 5=3^3\times 5^2$

Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement = $\frac{3^3\times 5^2}{5^5} = \frac{3^2}{5^{5-2}}$

= $\frac{3^3}{5^3} = \frac{27}{125}$

5 0

3 years ago

For which function is f(x) equal to f^1(x) ( answer choices in picture )

Sonja [21]

Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

7 0

3 years ago

Given the problem below what mistake did Bob make in solving the equation? Bob and his friends paid $30 for 3 sandwiches and and

storchak [24]

Answer:

Bob forgot to distribute 3 to 1.50 in the parentheses

Step-by-step explanation:

Bob made the mistake in his first step.

In the equation 3(x + 1.50) = 30, the 3 has to be distributed to both x and 1.50.

But, Bob only distributed it to x, which led him to get the wrong answer.

So, Bob's mistake when solving was that he forgot to distribute the 3 to 1.50

7 0

2 years ago