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Arisa [49]
3 years ago
11

Given the problem below what mistake did Bob make in solving the equation? Bob and his friends paid $30 for 3 sandwiches and and

3 bottles of water.
-Each sandwich cost the same amount.
-The bottles of water cost $1.50 each.
The equation 3(x + 1.50) = 30 can be used to determine x, the cost of each sandwich. Bob solved the equation using these steps: 3(x + 1.50) =30
3x + 1.50 = 30
3x = 28.50
x = 9.50
Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

Bob forgot to distribute 3 to 1.50 in the parentheses

Step-by-step explanation:

Bob made the mistake in his first step.

In the equation 3(x + 1.50) = 30, the 3 has to be distributed to both x and 1.50.

But, Bob only distributed it to x, which led him to get the wrong answer.

So, Bob's mistake when solving was that he forgot to distribute the 3 to 1.50

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Step-by-step explanation:

1/2 is the same as 3/6

There are three 1/6 in 3/6.

(3/6) ÷ (1/6) = 3

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a. the number of people at Friday's, Saturday's, and Sunday's performances combined.

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The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales
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Answer:

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=44 represent the sample mean

s=1.9 represent the sample standard deviation

n=40 sample size  

\mu_o =42 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 42, the system of hypothesis would be:  

Null hypothesis:\mu \leq 42  

Alternative hypothesis:\mu > 42  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

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