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Inessa [10]
2 years ago
5

The hypotenuse of a right triangle measures 6cm and one of its legs measures 3cm.Find the measure of the other leg. If necessary

, round to the nearest tenth.
Mathematics
2 answers:
belka [17]2 years ago
8 0

Answer:

5.2

Step-by-step explanation:

a^2+b^2=c^2

Where c is the length of hypotenuse

and a, b are lengths of the legs.

Put in 6 for c,

Put in 3 for a and you get 9+b^2=36

Subtract 9 from both sides and get b^2= 27

Then find the square root of both sides to get b, so the answer is the square root of 27.

The cloest square root is 5, then apporixmate the tenths value and see if they work.

Answer: 5.2

Nesterboy [21]2 years ago
3 0

Answer:

square root of 27, 5.2

Step-by-step explanation:

(I know I'm late but-)

3^2+b^2=6^2

9+b^2=36

b^2=27

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The vertices of a trapezoid are located at (1, 2), (3, 1), (3, 5), (1, 4). The trapezoid is translated 4 units to the right. Wha
padilas [110]

Answer:

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6 0
3 years ago
I need help, I don't know how to do it.
Sindrei [870]

Answer:

Step-by-step explanation:

to solve this problem we can use the Pythagorean theorem

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We have to find LU so we can proceed like this

x^2 + (x+1)^2 = LU^2

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we have to take only the positive value because a length can’t be negative.

2x^2 + 2x + 1 is positive for every value of x, so the final answer is

\sqrt{2x^2+2x+1}

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