It depends on what its asking for and what dimension it is. If its 2D, the area is lengthXwidth, and perimeter you would add all the side lengths. If its 3D, volume is lengthXwidthXheigth.
Answer:
Total cost is $205328
Step-by-step explanation:
Given data:
cost C(q) = 0.1 q^3 - 0.5 q^2 + 500 q + 200
current units q = 4 ( 4000 units )
The current level of production is 4000 ( 4 )units, and manufacturer is planning to upgrade this to 4100 ( 4.1 ) units
C'(q) = 3 * 0.1 q^2 - 2 * 0.5 q + 500
C'(q) = 0.3 q2 - q + 500
C(4.1) - C(4) ≈ C’(4) x Δq
≈ C’(4) x 0.1
≈ ( 0.3 * 4^2 - 4 + 500 ) x 0.1
≈ ( 0.3 * 16 - 4 + 500 ) x 0.1
≈ 500.8 x 0.1 ≈ 50.08
total cost = 4100 x 50.08 = $205328
You are adding 9/3 each time
so 2/3, 11/3, 20/3, 29/3, 38/3, 47/3
hope this helps