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lesya692 [45]
2 years ago
10

The students at Norton School were asked to name their favorite type of pet. Of the 430ilar results, about students surveyed, 25

8 said that their favorite type of pet was a dog. Suppose that only 100 students were surveyed, with similar results about how many students would say that a dog is their favorite types of pet?
Mathematics
1 answer:
elena-s [515]2 years ago
5 0

Answer: 60

Step-by-step explanation:

From the question, we are informed that 430 students were surveyed and 258 said that their favorite type of pet was a dog. The fraction/decimal of those that chose dog as their favorite pet will be:

= 258/430

= 3/5

= 0.6

Suppose that only 100 students were surveyed, the number of students that would say that a dog is their favorite types of pet will be:

= 0.6 × 100

= 60

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slope = m=(y2-y1)/(x2-x1)

m= (4-5)/(1-(-2))

m= -1/(1+2)

m=-1/3

Choice C

 

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Answer:

15%

Step-by-step explanation:

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Fill in the blanks below.
Dmitry_Shevchenko [17]

Answer:

a) <em>Slope of the line m = ∞</em>

<em>b) Slope of the line  m =0</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Step(i):-</em></u>

<em>Given points are ( 7,7) and (7,-8)</em>

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{-8-7 }{7-7  } = \frac{-15}{0} = infinite<em />

<em>                   m = ∞</em>

<u><em>Step(ii):-</em></u>

Given points are (-6,7) and (9,7)

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{7-7  }{9-(-6)  } = \frac{0}{15} = 0<em />

<em>Slope of the line  m =0</em>

6 0
3 years ago
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