9514 1404 393
Answer:
18
Step-by-step explanation:
Solve the first for a, then substitute into the second.
a = 27/(5b^2)
Then ...
(27/(5b^2))^2·b = 135
27^2/(5^2·135) = b^3 = 27/125
b = ∛(27/125) = 3/5
a = 27/(5(3/5)^2) = 15
__
The expression of interest is ...
a +5b = 15 + 5(3/5) = 15 +3
a +5b = 18
Diameter of the basketball rim = 18 inches
Circumference of the standard basketball = 30 inches
Area of circle = π r²
Basketball rim = 3.14 * (18/2)² = 3.14 * 9² = 3.14 * 81 = 254.34 in²
Circumference of a circle = 2 π r
30 = 2 * 3.14 * r
r = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches
Standard basketball = 3.14 * (4.78)² = 3.14 * 22.85 = 71.75 in²
254.34 - 71.75 = 182.59 in²
Answer:
(1.37) AUB = { 1,2,3,4,5,6}
(1.38) AUC = { 1,2,3,4,5 }
(1.39)BUC = { 1,2,3,4,5,6}
(1.40) { 2,4 }
(1.41) { 1,3,5 }
(1.42) { phi }
(1.43) AU(BUC) = { 1,2,3,4,5,6 }
(1.44) { phi }
(1.45) {1,2,3,4,5}
(1.46) { 1,2,3,4,5 }
Answer:
20
Step-by-step explanation:
f(x)= x/5
To solve for f(100), we substitute 100 for x everywhere in the equation:
f(100) = (100)/5
f(100) = 20
