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S_A_V [24]
2 years ago
10

2. Find the surface area of the regular pyramid shown to the nearest whole number.

Mathematics
1 answer:
hoa [83]2 years ago
5 0

Answer:

208m^2

Step-by-step explanation:

area of hexagon = 93.53 using its equation

area of single triangle = 0.5(6*6)

area of all triangles = 6(0.5(6*6))

total area = 207.53

NWN = 208

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A rectangle has an area of 72 swaure units. The width of the rectangle is 9 units. The length of the rectangle is 2x + 4. What i
vichka [17]

Answer:

8 units

Step-by-step explanation:

<u>Area of a rectangle</u> = <em>Width</em> multiplied by Length

Substitute in all the known numbers into this formula to get

<u>72</u> = <em>(9)</em> × (2x+4)

Solve the equation for x, to find out the length

9(2x+4)=72

2x+4=72/9

2x+4=8

2x=8-4

2x=4

x=4/2

x=2

Length of the rectangle = (2x+4)

2(2)+4

4+4=8

5 0
3 years ago
Stuck, need help please.
Maurinko [17]

Answer:

22.5 lbs

Step-by-step explanation:

First you find the cubic feet. That is the volume of the object which is length*width*height.

In your example, they are using inches. So you have to convert all units to feet. That would be 0.5 inches, 0.5 inches, and 5/3 inches. The volume would be 0.5*0.5*5/3 which is about 5/12 cubic feet

You then take that 5/12 cubic feet and multiply it by the 54 lbs/cubic foot. The answer would be 22.5 lbs

7 0
3 years ago
Find b: If a = 9 and c = 15<br> С<br> a<br> b
pogonyaev

Answer:

b=12

Step-by-step explanation:

a^2+b^2=c^2

(9×9) + b^2= 15×15

81+ b^2= 225

-81. -81

b^2=144

√. √

b= 12

3 0
3 years ago
Read 2 more answers
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

du=dx         v=2\cdot{e^(2x)}

\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du

\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx

\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C

We can therefore determine that if x tends to 0 the limit is -1

\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1

5 0
3 years ago
Line AC is tangent to circle O at point C<br> What is the measure of OAC?
Nuetrik [128]
AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees

The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180

Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees

Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90. 
7 0
3 years ago
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