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1 year ago

What is the perimeter of this rectangle pls help

Mathematics

2 answers:

alisha [4.7K]1 year ago

6 0

Answer:

Step-by-step explanation:

Perimeter of a shape = sum of all lengths of sides

⇒ Perimeter of a rectangle = (2 × width) + (2 × length)

From inspection of the rectangle:

width = 4
length = 8

⇒ Perimeter = (2 × 4) + (2 × 8)

= 8 + 16

= 24

mafiozo [28]1 year ago

4 0

P=2L+2W
P=(2*4)+(2*8)
P=8+16
P=24

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velikii [3]

Answer:

$y-6 = -\frac{1}{2} (x+1)$

Step-by-step explanation:

For this case we have two points given (-1,6) and (1,5)

And we want to complete the point slope equation of the line:

$y-6 = m(x-x_o)$

We need to find the slope and we can use the following formula:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

And replacing the info we got:

$m= \frac{5-6}{1-(-1)}=-\frac{1}{2}$

And then the equation would be given by:

$y-6 = -\frac{1}{2} (x- (-1))$

And our final answer would be:

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3 years ago

What is (9^4)^2?<br> And what is (6^1)^0?

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Answer:

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Step-by-step explanation:

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3 years ago

If twelve pounds of nails cost $3.84,what is the unit cost

Murljashka [212]

Hey!

---------------------------------------------

Solution:

12 pounds = $3.84

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Answer:

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3 years ago

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Frank, who lives in Texas, and his sister Lilly, who lives in Japan, correspond regularly. From what he can tell from the postma

Hoochie [10]

Question:

The available options are:

(A) There is convincing evidence that there is no difference in the mean delivery times.

(B) There is convincing evidence that there is a difference in the mean delivery times.

(C) There is convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(D) There is not convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan. (E) The t-test cannot be used for sample sizes that are this small.

Answer:

The correct option is;

(A) There is convincing evidence that there is no difference in the mean delivery times.

Step-by-step explanation:

Here we have the formula for the two-sample t-test given s;

$t =\frac{\overbar\overline{\rm x}_1 - \overbar\overline{\rm x}_2 }{\sqrt{\frac{\sigma ^2_1}{n_1} } +\frac{\sigma ^2_2}{n_2} }}$

To Texas N₁ = 12, $\overline{\rm x}_1$ =8.74 σ₁ = 2.92 SE Mean₁ = 0.84

To Japan N₂ = 9 $\overline{\rm x}_2$ = 6.75 σ₂ = 2.56 SE Mean₁ = 0.85

t = 1.667

Where the null hypothesis is

mu To Texas = mu To Japan and the alternative is

mu To Texas > mu To Japan

Here since the observed P value of P = 0.058 is greater than the significance level of 0.05 we fail to reject the null hypothesis and we will therefore, not accept the alternative hypothesis.

Hence, there is convincing evidence that there is no difference in the mean delivery times.

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3 years ago

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3 years ago

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