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vlabodo [156]
3 years ago
9

Solve the inequality. Graph the solution.2(5 – 3x) < x-4(3 - x)​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

<em>x</em>>2

Step-by-step explanation:

The first thing you need to do is distribute.

2 time 5 and 2 time -3x; -4 times 3 and -4 times -x.

After that you would get 10-6x < x-12+4x.

Now combine like terms. The only like terms are on the right side: x and 4x.

Now it's 10-6x < 5x-12.

Now put <em>x</em><em> </em>on one side. I prefer to work with a positive <em>x</em> so I would move it to the right.

Now it's 10 < 11x-12.

Isolate the <em>x</em><em>.</em><em> </em>Move the -12 first

Now it's 22<11x.

Divide by 11 next.

Now it's 11<x.

Switch it around so it's easier to interpret for the graph.

Final written inequality is x>11.

Graph the line x= 11 but with a dotted line because it is not equal to 11.

Color in everything to the right of the line because everything greater than x is to the right.

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pentagon [3]

Option A:

\mathrm{ABCD} \sim \mathrm{GFHE}

Solution:

ABCD and EGFH are two trapezoids.

To determine the correct way to tell the two trapezoids are similar.

Option A: \mathrm{ABCD} \sim \mathrm{GFHE}

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

Option B: \mathrm{ABCD} \sim \mathrm{EGFH}

In the given image length of AB ≠ EG.

So, \mathrm{ABCD} \sim \mathrm{EGFH} is the not the correct way to complete the statement.

Option C: \mathrm{ABCD} \sim \mathrm{FHEG}

In the given image length of AB ≠ FH.

So, \mathrm{ABCD} \sim \mathrm{FHEG} is the not the correct way to complete the statement.

Option D: \mathrm{ABCD} \sim \mathrm{HEGF}

In the given image length of AB ≠ HE.

So, \mathrm{ABCD} \sim \mathrm{HEGF} is the not the correct way to complete the statement.

Hence, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

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2 years ago
Number lines for 43.586 to the nearest tenths, hundredths , ones
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Tenths 43.5
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2 years ago
Write the equation x² + 6x + y² – 8y = 19 in standard form.
kirza4 [7]

Answer:

Formula used :

  • <u>x²+2xy+y²</u><u> </u><u>=</u><u> </u><u>(x+y)²</u>
  • <u>x²-2xy+y²</u><u> </u><u>=</u><u> </u><u>(x-y)²</u>

→{x}^{2}  + 6x +  {y}^{2}  - 8y = 19 \\  ({x}^{2}  + 2.3.x +  {3}^{2} ) +({y}^{2}  - 2.4.y +  {4}^{2} ) = 19 +  {3}^{2}  +  {4}^{2}  \\  {(x + 3)}^{2}  +  {(y - 4)}^{2}  = 19 + 9 + 16 \\  \boxed{ {(x + 3)}^{2}  +  {(y - 4)}^{2}  = 44}✓

  • <u>3) (x+3)²+(y-4)²=44</u> is the right answer.
8 0
2 years ago
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Each carton of eggs cost $3 make a table and an equation
dolphi86 [110]

Answer:

y = 3x

Step-by-step explanation:

x is number of cartons of eggs

y is cost

cost increases by 3 for every carton of eggs, so slope is 3

x and y intercepts are zero because there is no cost when there are no eggs

equation: y = 3x

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Whole number just means a number with no fraction or intger also 1 - infinity

3 0
3 years ago
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