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vlabodo [156]
3 years ago
9

Solve the inequality. Graph the solution.2(5 – 3x) < x-4(3 - x)​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

<em>x</em>>2

Step-by-step explanation:

The first thing you need to do is distribute.

2 time 5 and 2 time -3x; -4 times 3 and -4 times -x.

After that you would get 10-6x < x-12+4x.

Now combine like terms. The only like terms are on the right side: x and 4x.

Now it's 10-6x < 5x-12.

Now put <em>x</em><em> </em>on one side. I prefer to work with a positive <em>x</em> so I would move it to the right.

Now it's 10 < 11x-12.

Isolate the <em>x</em><em>.</em><em> </em>Move the -12 first

Now it's 22<11x.

Divide by 11 next.

Now it's 11<x.

Switch it around so it's easier to interpret for the graph.

Final written inequality is x>11.

Graph the line x= 11 but with a dotted line because it is not equal to 11.

Color in everything to the right of the line because everything greater than x is to the right.

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Make p the subject of the formula A=p+prt÷100​
mario62 [17]

Answer:

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Step-by-step explanation:

a = p + prt ÷ 100

a - prt = p ÷ 100

a - prt x 100 = p

Hope this helps. :)

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Answer:a

Step-by-step explanation:did it

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Read 2 more answers
The function h(x) = x2 + 14x + 41 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. S
denpristay [2]
Given the function h(x)=x^2+14x+41, to solve by completing square we procced as follows;
x^2+14x+41=0
x^2+14x=-41
but;
c=(b/2)^2
and b=14
hence;
c=(14/2)^2=49
substituting the value of c in the expression we get:
x^2+14x+49=-41+49
x^2+14x+49=8
(x+7)^2=8
this can be written in vertex form;
h(x)=a(x-h)^2+k
where:
(h,k) is the vertex;
thus
(x+7)^2=8
h(x)=(x+7)^2-8
hence the vertex will be at the point:
(-7,-8)
3 0
3 years ago
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