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frutty [35]
4 years ago
7

Can someone help me please ?? :)

Mathematics
2 answers:
ki77a [65]4 years ago
8 0
The answer would be 1/8 because when 1/8 is divide into the endpoints of AB you will recieve 1/8 of the endpoint numbers. Like 1/8 of 4 would be written as 1/8 times 4/1 since its a fraction multiply 1 times 4 and 8 times 1 to get 4/8. 4 goes into 4 one time and into 8 2 times giving you 1/2. Hope this helped. If you ever need help with math use this calculator and bookmark it so you can have it when you need it https://www.symbolab.com/
SIZIF [17.4K]4 years ago
6 0
I think it is A iam not sure sorry if I am wrong
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How do I solve this ?
Vinil7 [7]

Answer:

B, or in other words, the last solution is correct.

Step-by-step explanation:

Parallel lines haves the same slope, meaning that Street 2 will have the same slope as Street 1. Street one, according to the graph, has a slope of 1. Thus, Street 2 will have a slope of 1.

By this logic, we can get rid of A and C as choices, as they have a slope of -2 or 2. Now we have choices B and D left.

It can't be B, as the slope is -1, not 1.

Therefore, the answer is D.

5 0
3 years ago
Place (dlick and drag) one option from each of the lists below Into Its corresponding box to
earnstyle [38]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-1}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-1}\implies 3}}

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{3}(x-\stackrel{x_1}{1}) \\\\\\ y-10=3x-3\implies y=3x+7

5 0
2 years ago
Help me algebra are and circumference pls
Anvisha [2.4K]
The question is basically asking you how much area of the yard the pool takes up, in essence the area the pool takes up.

So we are going to find the area of the pool.

Area of pool is = pi x r^
= 3.14 x 7^2
= 153.86 ft^2

Therefore the pool takes up 153.86 ft^2 of space.
6 0
3 years ago
Read 2 more answers
If a hallway measuring 90 feet by 7 feet requires 1/2 a fluid ounce of cleaning solution per square foot, how much cleaning solu
kirill115 [55]
90ft by 7ft gives an area of:
90 x 7 = 630 sq ft

1/2 fl oz is needed for each square foot

630 x 1/2 = 315 fl oz required.
4 0
3 years ago
The lengths of the sides of a square are 5 cm. find the length of the diagonal
jenyasd209 [6]

Answer:

square root (50) = 7.071

Step-by-step explanation:

Using Pthagoras' theorem, the diagonal length is \sqrt{x} ax^{2} +bx^{2}.

Therefore, the diagonal length is the square root of 5^2+5^2,

= \sqrt{x} 25+25

= \sqrt{x} 50

= 7.071

8 0
3 years ago
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