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babunello [35]
2 years ago
7

WILL CHOOSE BRAINLIEST!!! The oxford square is approximately 300 feet on each side. What is the length of the diagonal square?

Mathematics
2 answers:
Naddik [55]2 years ago
7 0

Answer:

if no one is gonna use it why don't i lol sry guys but i could be the reason the person above me gets brainlist

Step-by-step explanation:

Marina CMI [18]2 years ago
5 0

Answer:

424 ft and 3 inches

Step-by-step explanation:

To calculate the diagonal of a square, multiply the length of the side by the square root of 2 --> d = a√2

a² + a² = diagonal²

diagonal = √(a² + a²) = √(2 x a²) which simplifies to diagonal = a√2

If area is given --> d = √(2*area)

Knowing square perimeter --> d = (perimeter/4)*√2

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The answer is to this question is c (5,-7)
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3 years ago
The theory that it is reasonable to chose the simpler theory when choosing between two competing theories of equal explanatory v
Vesnalui [34]

Answer:

Occam’s razor theory.

Step-by-step explanation:

This theory is known as Occam’s razor theory.

It's a theory based on the principle whereby we give precedence to simplicity. It states that out of two competing theories, the one with the simpler explanation of an object should be embraced over the other. The reason is that the philosopher William of Ockham said that "objects are not meant to be multiplied beyond absolute necessity.”

This definition resonates with what is explained in the question.

Thus, the theory is as explained.

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3 years ago
Eric has 10 cookies and, gives 5 cookies to Brad. How many do you have left.
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He will have 5 cookies left
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3 years ago
Read 2 more answers
If N is the population of the colony and t is the time in​ days, express N as a function of t. Consider Upper N 0 is the origina
lesya [120]

Answer:

(a)N(t)=Noe^{kt}

(b)5,832 Mosquitoes

(c)5 days

Step-by-step explanation:

(a)Given an original amount N_o at t=0. The population of the colony with a growth rate k \neq 0, where k is a constant is given as:

N(t)=Noe^{kt}

(b)If N_o=1000 and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)

Therefore, our model is:

N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t

In 3 days time

N(3)=1000\cdot1.8^3=5832

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0
3 years ago
Read 2 more answers
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
oksano4ka [1.4K]

Answer: -1.0018*10^42

Step-by-step explanation:

The Euler Method in numerical analysis is used to approximate the solution to an initial value problem using the tangent line to the solution curve through the (x0,y0) to obtain such approximations.

The euler method equation is:

Yn+1 = Yn + h*f(Xn,Yn)

Where n = number of steps, h = Xn+1 - Xn, f(Xn,Yn) is the slope of the curve at (Xn,Yn).

Variables given in the equation

Y(X=0) = 9,

X0 = 0.

h = step = 0.2

f(X,Y) = X^2*Y - 12*Y^2

B

For the first step, n = 0 in the euler equation. Therefore we have:

Y1 = Y0 + h*f(X0,Y0)

Substituting the Y0 = 9 and X0 = 0 into the function f(X,Y) = X^2*Y - 12*Y^2 = 0^2*9 - 12*9^2 = -972.

Therefore Y1 = 9 + 0.2*(-972) = -185.4.

For n = 1

Repeating the same step with X1 = X0 + h = 0 + 0.2 = 0.2,

Y1 = -185.4,

h = 0.2.

Substitute the variables into the equation Y2 = Y1 + h*f(X1,Y1) and f(X1,Y1) = X1^2*Y1 - 12*Y1^2

Y2 = -82682.4672.

Continue the iterations following the steps above till the result is reached.

The summary of the iteration.

When n = 0, X = 0, Y = -185.4

When n = 1 , X = 0.2, Y = -82682.4672

When n = 2 , X = 0.4, Y = -1.6407*10^10

When n = 3, X = 0.6, Y = -6.4609*10^20

When n = 4, X = 0.8, Y = -1.0018*10^42

4 0
3 years ago
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