Answer:
The answer for this question is <u><em>2√3 + 2.</em></u>
Step-by-step explanation:
<u><em>6√3 - 4√3 + 2</em></u>
<u><em>= ( 6 - 4 )√3 + 2</em></u>
<u><em>= 2√3 + 2 </em></u><em> </em><u><em> ans...</em></u>
<u><em></em></u>
Hope its helpful :-)
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Taylor series is 
To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have
f(x) = ln(x)

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Since we need to have it centered at 9, we must take the value of f(9), and so on.
f(9) = ln(9)

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Following the pattern, we can see that for
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This applies for n ≥ 1, Expressing f(x) in summation, we have

Combining ln2 with the rest of series, we have

Taylor series is 
Find out more information about taylor series here
brainly.com/question/13057266
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Answer
i don't think people wanna do it
Step-by-step explanation:
If B is the midpoint of AC, then AB = BC.
We have AB = x + 5 and BC = 2x - 11.
Therefore we have the equation:
x + 5 = 2x - 11 <em>subtract 5 from both sides</em>
x = 2x - 16 <em>subtract 2x from both sides</em>
-x = -16 <em>change the signs</em>
x = 16
Put the value of x to the expression x + 5:
AB = 16 + 5 = 21
<h3>Answer: AB = 21</h3>
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