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2 years ago

NEED HELP NOW!!!!!!!

Mathematics

1 answer:

anzhelika [568]2 years ago

4 0

Step-by-step explanation:

the area of a triangle is

baseline × height / 2

the baseline (where the height hits at a 90° angle) is 4 m.

the height is 3.7 m.

so, the area is

4 × 3.7 / 2 = 2 × 3.7 = 7.4 m²

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#3-4 PLEASE HELP ASAP

Pie

Answer:

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Step-by-step explanation:

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3 years ago

the perimeter of a rectangular garden is 50 meters and area is 150 meters square . calculate the length and breadth of the garde

makkiz [27]

Answer: The two sides are 15m and 10m.

Step-by-step explanation:

Area = l x w

150 = l x w

There are two solutions for l

l 1= P/4+1/4√P2﹣16A

=50/4+1/4·√50^2﹣16·150=15m

l2 = P/4﹣1/4√P2﹣16A

=50/4﹣1/4·√50^2﹣16·150=10m

6 0

3 years ago

A professor records the difference between the marks scored by the students in the class test last week and those scored in the

dezoksy [38]

Answer: $(10.82\ , 13.18)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\mu\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n= 35 , large sample (n>30)

Mean difference : $\overline{x}=12$

Standard deviation : $\sigma=3$

Significance level : $\alpha=- 1-0.999=0.001$

Critical value : $z_{\alpha/2}=z_{0.0005}=3.4807567$

Now, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students will be :-

$12\pm\ (3.4807567)\dfrac{2}{\sqrt{35}}\\\\=12\pm1.18\\\\=(10.82\ , 13.18)$

Hence, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students = $(10.82\ , 13.18)$

4 0

2 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

3 years ago

Please asap correct answer gets brainliest

weeeeeb [17]

Answer: 36 square units

Step-by-step explanation:

Divide the figure into 2 shapes: a rectangle and a triangle. Count the squares to find the dimensions of each figure. The rectangle has a width of 4 units and a length of 6 units. The triangle has a base of 6 units and a height of 4 units.

The formula for the area of a rectangle is length * width. The area of the rectangle is 4*6 = 24 square units.

The formula for the area of a triangle is (base * height)/2. The area of the triangle is (4*6)/2 = 24/2 = 12 square units.

Add the areas of both the rectangle and triangle. 24+12 = 36 square units.

8 0

1 year ago