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Pie
2 years ago
14

A spinner and 4 cards are shown below:

Mathematics
2 answers:
elena55 [62]2 years ago
7 0

Answer:

1 over 20

Step-by-step explanation:

<u><em>Given that:</em></u>

<em>a spinner and 4 cards</em>

<u><em>A Spinner ⇒ 5 equal sectors;Color: Blue,Purple,Yellow,Red,Green</em></u>

<em>Arrow point at purple </em>

<u><em>Four cards ⇒ Color : Red,Yellow,Blue,Pink</em></u>

<em>Jane spins the spinner & selects card without looking.</em>

<em>To Find - Probability spinner stops at purple & select pink card.</em>

<u><em>Solve:</em></u>

<em>Multiply 4 (the number of cards) with 5 (The number of equal sectors)</em>

<em />\frac{1}{5}\times\frac{1}{4}=\frac{1}{20}          {1 × 1 = 1}    {5×4=20}

<u><em>~lenvy~</em></u>

Mama L [17]2 years ago
7 0

Answer:

1 over 20

Step-by-step explanation:

Given the following:

1 spinner and 4 cards

A Spinner which has 5 equal sectors;Color: Green, Blue,Purple,Yellow,Red.

{Arrow point at purple}

Four cards ⇒ which color are Red,Yellow,Blue,Pink

Jane spins the spinner & selects card without looking.

To Find →  Probability spinner stops at purple & select pink card.

Since, purple and pink only has one in each of Spinner/card

Thus,

Spinner (5 equal sectors - 1/5}

Card {4 cards - 1/4}

1/4 × 1/5 = 1/20

Hence, probability spinner stops at purple & select pink card is [A] 1/20

[RevyBreeze]

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2 years ago
Is a relation always a function? Is a function always a relation? Explain.
katen-ka-za [31]

A function is always a relation but relation is not always a function

<u>Solution:</u>

Given that, we have to explain Is a relation always a function and is a function always a relation

Note that both functions and relations are defined as sets of lists.  

In fact, every function is a relation. However, not every relation is a function.  A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y.

That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. Let me give you a relation between them that is not a function;

X = { 1, 2, 3 }

Y = { a , b , c, d }

Relation from X to Y : { (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c

Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

This is a function since each element from X is related to only one element in Y. Note that it is okay for two different elements in X to be related to the same element in Y. It's still a function, it's just not a one-to-one function.

So, we can say that function is a type of relation.

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But when a relation occurs it may be a function but need not be always a function.

Hence, a function is always a relation but relation is not always a function.

8 0
3 years ago
Divide 29 into two parts so that the sun of the squares of the parts is 425.Find the value of each Part.
Taya2010 [7]

Answer:

13 and 16

Step-by-step explanation:

let the 2 parts be x and y, then

x + y = 29 → (1) and

x² + y² = 425 → (2)

From (1) → x = 29 - y → (3)

substitute x = 29 - y into (2)

(29 - y)² + y² = 425 ( expand factor )

841 - 58y + y² + y² = 425 ( rearrange into standard form )

2y² - 58y + 416 = 0 ← in standard quadratic form

divide all terms by 2

y² - 29y + 208 = 0

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These are - 13 and - 16, hence

(y - 13)(y - 16) = 0

equate each factor to zero and solve for y

y - 13 = 0 ⇒ y = 13

y - 16 = 0 ⇒ y = 16

substitute these values into (3)

x = 29 - 13 = 16 and x = 29 - 16 = 13

The 2 parts are 13 and 16


4 0
3 years ago
Read 2 more answers
The access code for a​ car's security system consists of sixsix digits. the first digit cannot be zerozero and the last digit mu
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There are six digits. The first can be anything but 0. There are 9 other choices.
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Repetitions allowed.
9 * 10 * 10 * 10 * 10 * 5 The last digit must be odd.
450,000 <<<< answer.

No repetitions 
Sorry this requires more thought.
7 0
3 years ago
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