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anastassius [24]
3 years ago
11

21)what is the simplified form of the following expression? -(8n-5v) a)-8n 5v b)8n 5v c)8n-5v d)-8n-5v

Mathematics
2 answers:
Brrunno [24]3 years ago
6 0
When you remove the parentheses the sign preceding the parentheses changes all the signs inside to the opposite so 8 becomes negative 8 and 5 becomes a positive 5. so the answer would be -8n+5v
stiks02 [169]3 years ago
4 0
Right answer is A
-8n+5v
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Martin has 28 basketball ball cards. Martin has 12 times as many basketball cards as Josie. Josie has 29 more cards than kal. Ho
Alona [7]

Answer:

28...?

Step-by-step explanation:

Well, the question states that Martin has 28 basketball cards at the start of the question, and asks how many he has at the end. Martin still has 28 cards. Unless part of the question was cut, then this is your answer.

7 0
3 years ago
Calculate the value of P and of Q that satisfy the following simultaneous linear equations.
luda_lava [24]

  1. 0.5p -3q =11
  2. 5p +6q =2

1) ×-2

--> 3. -p +6q =-22

2) - 3)

6p =24

p =4

sub into 2)

5(4) +6q =2

20 +6q =2

6q =2 -20 =-18

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5 0
3 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
3 years ago
PLZ PLZ PLZ HELP ME :( IM CRYING RIGHT
nalin [4]

Answer:

Step-by-step explanation:

x = 150

1/3 x =  50

x -20 = 30

x -10 = 140

Are u ok ????

6 0
3 years ago
What is the value of x in the solution to this system of equations?
liberstina [14]

Answer:

x = 11

Step-by-step explanation:

Given the expression;

5x+2y=67 ...1

x=3y−7 ....2

Substitute 2 into 1

5(3y-7)+2y = 67

15y - 35 + 2y = 67

17y = 67+35

17y = 102

y = 102/17

y =6

Recall that x = 3y - 7

x = 3(6) - 7

x = 18 - 7

x = 11

Hence the value of x is 11

6 0
3 years ago
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