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dexar [7]
2 years ago
12

a sector of a circle has a central angle measure of 60°, and an area of 14 sq inches, what is the area of the entire circle​

Mathematics
2 answers:
damaskus [11]2 years ago
7 0

Answer:

The answer is below!!

Step-by-step explanation:

The formula used to find the area of a circlular sector - a pie-shaped part of a circle. ... π. 4. 2. ·. 86. 360. = 12.01. What the formulae are doing is taking the area of the whole ... So for example, if thecentral angle was 90°, then the sector would have an area equal to one ... r is the radius of the circleof which the sector is part.

Hope I Helped!!

:)

Nina [5.8K]2 years ago
6 0

Answer:

area of entire circle = 84 in²

Explanation:

\sf \dfrac{\theta}{360} *\pi *r^2 = Area \ of \ sector

===========

\sf \rightarrow  \dfrac{60}{360} *\pi *r^2 = 14

\sf \rightarrow \dfrac{1}{6}\pi *r^2 = 14

\sf \rightarrow r^2 = \dfrac{14*6}{ \pi}

\sf \rightarrow r = \sqrt{\dfrac{84}{ \pi} }

\sf \rightarrow r = 5.17\ in

Area of circle:

\sf \pi r^2

=====

\hookrightarrow \sf \pi (5.17)^2

\hookrightarrow \sf 84\ in^2

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3 years ago
The magnitude and direction of two forces acting on an object are 100100 ​pounds, S7878degrees°​E, and 5050 ​pounds, N5353degree
amm1812

Answer:

  138.06 lb N86.1°E

Step-by-step explanation:

There are several ways you can work this. One of the most straightforward is to resolve each vector into its north and east components, add those, and then covert the result back to magnitude and direction.

A diagram can help immensely.

We note that S78°E is the same as E12°S. Since we're used to seeing the coordinate system with the +x axis aligned with east, it can be convenient to think of the first force as 100 lb at -12°.

The angle of the second force is N53°E, which can be expressed as E37°N. Then in x-y coordinates, this force is 50 lb at +37°.

The components of the sum are the sum of the components:

  R = F1 +F2 = (100cos(-12°) +50cos(37°), 100sin(-12°) +50sin(37°))

  = (137.747, 9.300)

The the magnitude of the resultant is computed using the Pythagorean theorem:

  ||R|| = √(137.747² +9.300²) ≈ 138.06

and the angle is computed using the arctangent function. Here, our diagram tells us the angle is in the first quadrant, so is positive (relative to +x, or East).

  ∠R = arctan(9.300/137.747) ≈ 3.9°

__

We want to express the answer in terms similar to the way the given forces are expressed, so we want the angle relative to north. The resultant is then described by ...

  R = 138.06 lb at N86.1°E

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3 years ago
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