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Mama L [17]
3 years ago
5

How many square feet of outdoor carpet will need for this hole

Mathematics
2 answers:
Arada [10]3 years ago
5 0
Green area - triangle area = 72-9 = 63 square feet
Artist 52 [7]3 years ago
5 0

Answer:

Area=63 square foot

Step-by-step explanation:

The dimensions of the outdoor carpet which is rectangle in shape are:

L=6 ft and w=12 ft.

The dimensions of the indoor carpet that is triangle in shape are:

b=3 ft and h=9 ft.

Now, area of the outdoor= Area of the green region-Area of triangular region

Area=l{\times}b-\frac{1}{2}{\times}b{\times}h

Area=6(12)-\frac{1}{2}{\times}3{\times}6

Area=72-9

Area=63 square foot

Thus, the area of the outdoor carpet is 63 square foot.

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The perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions.
Vanyuwa [196]

Answer:

20 m by 10 m

Step-by-step explanation:

let w be width and l be length , then

2(l + w) = 60 ( divide both sides by 2 )

l + w = 30 ( subtract w from both sides )

l = 30 - w → (1)

lw = 200 → (2)

Substitute l = 30 - w into (2)

w(30 - w) = 200 ← distribute parenthesis on left side

30w - w² = 200 ( subtract 200 from both sides )

30w - w² - 200 = 0 ( multiply through by - 1 )

w² - 30w + 200 = 0 ← in standard form

(w - 10)(w - 20) = 0 ← in factored form

Equate each factor to zero and solve for w

w - 10 = 0 ⇒ w = 10

w - 20 = 0 ⇒ w = 20

Substitute these values into (1)

l = 30 - 10 = 20

l = 30 - 20 = 10

dimensions of field is 20 m by 10 m

4 0
2 years ago
Read 2 more answers
Algebra help please?
Alika [10]

Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20  = -1.125x^2 + 6x + 40.

From there use algebraic steps to find out what x is ( the break - even point ).

0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40

0.855625x - 4x + 20 = 1.265625x + 6x + 40

-0.41x - 4x + 20 = 6x + 40

-4.41x + 20 = 6x + 40

20 = 10.41x + 40

-20 = 10.41x

-1.92122958694 = x

Rounded to the nearest tenth it's -1.9 = x.

Tell me if I got something wrong :)

3 0
3 years ago
Is knowing the coordinates of the vertex of a parabola enough to determine the domain and range?
puteri [66]

The <em>correct answers</em> are:


C) No: we would need to know if the vertex is a minimum or a maximum; and

C)( 0.25, 5.875).


Explanation:


The domain of any quadratic function is all real numbers.


The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.


If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.


There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.


The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).

5 0
3 years ago
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What is the answer to this problem ?
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If something is to the power of 1/2, it is the same as the square root of that number. So, what's the square root of 49?
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3 years ago
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Y+47x12.6 rewrite the equation below as a function of x
ella [17]
I'm confused is the x a × symbol or the letter x?
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