Part (a) Finding the probability of either A or B
We are told that events A and B are mutually exclusive. This means they cannot happen at the same time. We can say P(A and B) = 0
Furthermore,
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.4 + 0.2 - 0
P(A or B) = 0.6
<h3>Answer: 0.6</h3>
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Part (b) Finding the probability of neither A nor B
P(A or B) + P(neither A nor B) = 1
P(neither A nor B) = 1 - P(A or B)
P(neither A nor B) = 1 - 0.6
P(neither A nor B) = 0.4
The reason why this works is to imagine throwing a dart at the Venn diagram. You'll either...
- you land in A or B (pick one but not both), OR,
- you'll land outside both regions A and B.
One or the other must happen. Both events cannot happen simultaneously.
<h3>Answer: 0.4</h3>
Answer:
Number of student tickets = 325
Number of adult tickets = 404
Step-by-step explanation:
Let,
x be the number of student tickets
y be the number of adult tickets
According to given statement;
x+y=729 Eqn 1
3x+5y=2995 Eqn 2
Multiplying Eqn 1 by 3
3(x+y=729)
3x+3y=2187 Eqn 3
Subtracting Eqn 3 from Eqn 2
(3x+5y)-(3x+3y)=2995-2187
3x+5y-3x-3y=808
2y=808
Dividing both sides by 2
Putting y=404 in Eqn 1
x+404=729
x=729-404
x=325
Hence,
Number of student tickets = 325
Number of adult tickets = 404
I think it will be 23 because you will divide 208 by 9 and you will get
23 r1
