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2 years ago

3x(x-y)-p(y-x) factorise by taking out the common factor

Mathematics

1 answer:

puteri [66]2 years ago

4 0

Answer:

Rewrite as

3x(x-y) -p[-(x-y)]

We factored out a minus from the second bracket. I chose the second bracket arbitrarily... You can chose the 1st bracket if you want.

Now when those two minus interact... They became Positive(From rules of sign Multiplication)

3x(x-y) + p(x-y)

Now factor out (x-y) from both

(x-y) [ 3x + p]

So that's our answer!!

(x-y)[ 3x + p ].

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Can someone help me please?

morpeh [17]

Heya bro!!

------------------------------------

If uh r asking about scientific notification then x must be in lowest form but decimal point is after 1.

So correct answer is 1.04 * 10^2 .

If uh wanna check multiply it.. Uh will get 104.

Hope it helps uh!

5 0

3 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

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3 years ago

Please help me I will give a brainly!!!!

nydimaria [60]

Answer:

Yes

Step-by-step explanation:

1 : The athlete's hands push the medicine ball forward. The medicine ball pushes the athlete's hands backward.

2: Friction

3: The first pair of action-reaction force pairs is: foot A pushes ball B to the right; and ball B pushes foot A to the left. The second pair of action-reaction force pairs is: foot C pushes ball B to the left; and ball B pushes foot C to the right

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2 years ago

Cu ochii iesiti din orbite propozitie dau coroana

Y_Kistochka [10]

Answer:

idfk lol hehe hope this helps

Step-by-step explanation:

5 0

2 years ago

The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c

Anestetic [448]

Answer:

a) The mean is $\mu = 60$

b) The standard deviation is $\sigma = 9$

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when $X = 55.5, Z = -0.5$