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2 years ago

Pls help I cant figure it out ;-;

Mathematics

2 answers:

Brums [2.3K]2 years ago

8 0

Ok so I even looked it up and it looked like it was coke so coke I guess

worty [1.4K]2 years ago

6 0

Answer:

coke red

Step-by-step explanation:

correct me if im wrong

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Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)

BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

$\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}$

so distance between A(-5,4) and B(3,4) is:

$\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}$

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

$\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}$

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

$\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}$

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

$\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}$

so fourth bush 9 units below of A.

8 0

1 year ago

9. PLEASE HELP ME

gizmo_the_mogwai [7]

Answer:

C. (3, 3)

Step-by-step explanation:

8 0

3 years ago

The specifications for manufacturing a steel rod stipulate that the length must be 8.225 ± 0.125 inches. The Minimum allowable l

zmey [24]

Answer:

Minimum - 8.1 inches

Maximum - 8.35 inches

Step-by-step explanation:

The specifications for manufacturing a steel rod stipulate that the length must be 8.225 ± 0.125 inches.

This means that the minimum length must not be 0.125 inches less than 8.225 inches and the maximum length must not be 0.125 inches greater than 8.225 inches.

The minimum length is therefore:

8.225 - 0.125 = 8.1 inches

The maximum length is therefore:

8.225 + 0.125 = 8.35 inches

6 0

3 years ago

3.) mr. smith’s class sold wrapping paper for $3.50 each and mr. davis’ class sold magazines for $2.75 each. together, the class

igor_vitrenko [27]

Answer:

The number of wrapping paper sold was 32 and the number of magazines sold was 40

Step-by-step explanation:

Let

x ----> the number of wrapping paper sold

y ----> the number of magazines sold

we know that

The classes sold 72 items

$x+y=72$ ----> equation A

The classes earned $222 for their school

$3.50x+2.75y=222$ ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The solution is (32,40)

see the attached figure

therefore

The number of wrapping paper sold was 32 and the number of magazines sold was 40

7 0

3 years ago

Find equivalent expressions for a+a+a+5+a+3 plz help

baherus [9]

4a+8
Add all A's together.
Add 5 and 3 together.

8 0

3 years ago

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