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erma4kov [3.2K]
2 years ago
7

Kyle designs and conducts a computer simulation with 25 trials and uses the data to create the relative frequency bar graph show

n. The graph shows the relative frequency of number rolls needed of a number cube in order to roll all of the odd numbers. According to the results of the simulation, what is the experimental probability that 6 or fewer rolls are needed to roll all of the odd numbers? Express your answer as a percent. ​

Mathematics
1 answer:
Ksivusya [100]2 years ago
6 0

Answer:

thirty-six, thirty six, 36%, thirty-six percent, thirty six percent, or 36 percent

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Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

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Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

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And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

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