Answer:
Step-by-step explanation:
![a = \frac{2b+1}{3b-1}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B2b%2B1%7D%7B3b-1%7D)
b = 2/3
![2b + 1 = 2*\frac{2}{3}+1\\\\=\frac{4}{3}+1\\\\=\frac{4}{3}+\frac{3}{3}\\\\=\frac{7}{3}\\\\3b-1 = 3*\frac{2}{3}-1\\\\=2- 1 = 1\\\\\\](https://tex.z-dn.net/?f=2b%20%2B%201%20%3D%202%2A%5Cfrac%7B2%7D%7B3%7D%2B1%5C%5C%5C%5C%3D%5Cfrac%7B4%7D%7B3%7D%2B1%5C%5C%5C%5C%3D%5Cfrac%7B4%7D%7B3%7D%2B%5Cfrac%7B3%7D%7B3%7D%5C%5C%5C%5C%3D%5Cfrac%7B7%7D%7B3%7D%5C%5C%5C%5C3b-1%20%3D%203%2A%5Cfrac%7B2%7D%7B3%7D-1%5C%5C%5C%5C%3D2-%201%20%3D%201%5C%5C%5C%5C%5C%5C)
![a = \frac{2b+1}{3b-1}\\\\a=\frac{\frac{7}{3}}{1}\\\\=\frac{7}{3}\\\\](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B2b%2B1%7D%7B3b-1%7D%5C%5C%5C%5Ca%3D%5Cfrac%7B%5Cfrac%7B7%7D%7B3%7D%7D%7B1%7D%5C%5C%5C%5C%3D%5Cfrac%7B7%7D%7B3%7D%5C%5C%5C%5C)
a = 7/3
b)
![\frac{2b+1}{3b-1}=a\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B2b%2B1%7D%7B3b-1%7D%3Da%5C%5C%5C%5C)
Cross multiply,
2b + 1 = a*(3b - 1)
2b + 1 = a*3b - 3*a
2b + 1 = 3ab- 3a
2b = 3ab - 3a - 1
2b - 3ab = -3a - 1
b(2 - 3a) = -3a - 1
![b =\frac{-3a - 1}{2 - 3a}](https://tex.z-dn.net/?f=b%20%3D%5Cfrac%7B-3a%20-%201%7D%7B2%20-%203a%7D)
For this case we have a function of the form:
H (t)
Where,
t: number of days
H: the daily high temperature
We have the point (0.29).
It means that the hottest day of the year had a temperature of 29 degrees.
Answer:
the hottest day of the year had a temperature of 29 degrees.
Answer: The answer is two football players pushing a tackling sled because obviously they are going in the same direction. So yeah your answer is B 100% sure!
Answer:
•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25
•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25
cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗
sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5