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vfiekz [6]
2 years ago
14

What do we do to both sides of this equation to solve?

Mathematics
2 answers:
anzhelika [568]2 years ago
8 0

Add 10 to both sides

Step-by-step explanation:

x-10 = 8

x - 10 + 10 = 8+ 10

x = 18

NeTakaya2 years ago
8 0

Step-by-step explanation:

Add 10 to both sides

or,x-10+10=8+10

or,x=18

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Brian and Mark are fishing. They both catch a fish. Brian's fish weighs 17 pounds less than Mark's fish. Mark's fish weighs 22 p
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5 pounds.

Step-by-step explanation:

22 - 17 = 5

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If you flip three fair coins, what is the probability that you’ll get two tails and one head in any order?
siniylev [52]

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1/ 3 is the probability of getting one head

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Alex is making cookies the recipe says that she has to make 224 g of sugar into the flower Alex his nose that one cup of this pa
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7 0
3 years ago
Suppose that when a transistor of a certain type is subjected to an accelerated life test, the lifetime x (in weeks) has a gamma
elena-14-01-66 [18.8K]

Answer:

a) P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

b) P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

Step-by-step explanation:

Previous concepts

The Gamma distribution "is a continuous, positive-only, unimodal distribution that encodes the time required for \alpha events to occur in a Poisson process with mean arrival time of \beta"

Solution to the problem

Let X the random variable that represent the lifetime for transistors

For this case we have the mean and the variance given. And we have defined the mean and variance like this:

\mu = 40 = \alpha \beta  (1)

\sigma^2 =320= \alpha \beta^2  (2)

From this we can solve \alpha and [/tex]\beta[/tex]

From the condition (1) we can solve for \alpha and we got:

\alpha= \frac{40}{\beta}    (3)

And if we replace condition (3) into (2) we got:

320= \frac{40}{\beta} \beta^2 = 40 \beta

And solving for \beta = 8

And now we can use condition (3) to find \alpha

\alpha=\frac{40}{8}=5

So then we have the parameters for the Gamma distribution. On this case X \sim Gamma (\alpha= 5, \beta=8)

Part a

For this case we want this probability:

P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

Part b

For this case we want this probability:

P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

6 0
3 years ago
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