All categories

2 years ago

What do we do to both sides of this equation to solve?

Mathematics

2 answers:

anzhelika [568]2 years ago

8 0

Add 10 to both sides

Step-by-step explanation:

x-10 = 8

x - 10 + 10 = 8+ 10

x = 18

NeTakaya2 years ago

8 0

Step-by-step explanation:

Add 10 to both sides

or,x-10+10=8+10

or,x=18

You might be interested in

A typical snake bite delivers 0.0045 grams of venom. Maria and Tammy were asked to write this number in scientific notation. The

Stolb23 [73]

Answer:

Maria

Step-by-step explanation:

A typical snake bite delivers 0.0045 grams of venom.

Maria wrote it in scientific notation as $4.5\times 10^{-3}$

Tammy wrote it in scientific notation as $4.5\times 10^{3}$

Any number can be written in the form of scientific notation as follows :

$N=a\times 10^b$ (a is real no and b is integer)

The given no is 0.0045.

There are 2 zeroes before 4. Also the decimal is there before 2 zeroes.

$0.0045=\dfrac{45}{10000}\\\\=\dfrac{45}{10}\times \dfrac{1}{1000}\\\\=4.5\times 10^{-3}$

Hence, Maria is correct.

6 0

3 years ago

To go bowling it costs $2 to rent shoes and then $3.25 for each game bowled. Which of the following functions gives the total co

likoan [24]

3.25g+2=t is your function

7 0

3 years ago

Read 2 more answers

Verbal expression x to the third power times y to the 4th power???

Molodets [167]

Step-by-step explanation:

First;

x to third power=x³

y to 4th power=y⁴

According to condition:

expression=x³ × y⁴

=x³y⁴

3 0

2 years ago

What is the length of the diagonal?

Anon25 [30]

The answer is $16\sqrt{8}$ i hope this answer helps you!

4 0

3 years ago

Read 2 more answers

Six friends attend a party. They form pairs for a game. How many different pairs are possible?

Leona [35]

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

5 0

3 years ago