If f(x)= 3x^3+17x^2+22x+8 and x+4 is a factor of f(x), then find ALL the zeros of f(x) algebraically.
1 answer:
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Answer:
1) (2x - 3)(x + 5)
2) 1.5, -5
3) Open upwards from both ends
4) Minimum
Step-by-step explanation:
Step 1:
The given polynomial is:
Taking out commons, we get:
This is the factorized form of the polynomial.
Step 2:
The zeros of the functions occur when the function is equal to zero.
i.e.
This means, the zeros of the polynomial are 1.5 and -5
Step 3:
The end behavior of a graph depends on its degree and the sign of leading coefficient. Since the degree is even and the coefficient is positive the graph of the polynomial will opens upwards from left and right side.
Step 4:
The given polynomial is a quadratic function with positive leading coefficient. Since it open vertically upwards, its vertex will be the lowest most point. So, the vertex will be the minimum of the function.