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irakobra [83]
3 years ago
5

show that the relation R in R define as R = {(a, b): a<_ b}, is reflexi when transistor but not symmetry​

Mathematics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

R is reflexive and transitive but not symmetric.

Step-by-step explanation:

R = {(a, b); a ≤ b}

Clearly (a, a) ∈ R as a = a.

R is reflexive.

Now,

(2, 4) ∈ R (as 2 < 4)

But, (4, 2) ∉ R as 4 is greater than 2.

R is not symmetric.

Now, let (a, b), (b, c) ∈ R.

Then,

a ≤ b and b ≤ c

→ a ≤ c

→ (a, c) ∈ R

R is transitive.

Thus, R is reflexive and transitive but not symmetric.

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Answer:

= -√6

Step-by-step explanation:

1) collect like terms by subtracting coefficients:

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2) calculate (3-4):

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3) the coefficient of -1 does not have to be written, but the negative sign remains:

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so therefore:

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vova2212 [387]
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\frac{n}{5} - 17 = 33

Second, we can start out our goal by trying to get the variable (n) on one side by itself and to equal something. Let's begin by adding 17 to each side of the problem.
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Third, we can now add the numbers on the right side of our problem. Simple. Add 33 + 17 to get 50.
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Fourth, we now have to multiply both sides by 5. Why? We are getting rid of the fraction so that the variable can become by itself.
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Answer: \fbox {n = 250}
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