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irakobra [83]
2 years ago
5

show that the relation R in R define as R = {(a, b): a<_ b}, is reflexi when transistor but not symmetry​

Mathematics
1 answer:
kati45 [8]2 years ago
5 0

Answer:

R is reflexive and transitive but not symmetric.

Step-by-step explanation:

R = {(a, b); a ≤ b}

Clearly (a, a) ∈ R as a = a.

R is reflexive.

Now,

(2, 4) ∈ R (as 2 < 4)

But, (4, 2) ∉ R as 4 is greater than 2.

R is not symmetric.

Now, let (a, b), (b, c) ∈ R.

Then,

a ≤ b and b ≤ c

→ a ≤ c

→ (a, c) ∈ R

R is transitive.

Thus, R is reflexive and transitive but not symmetric.

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yaroslaw [1]

Answer:

(x-5)(x+6)=0

Step-by-step explanation:

hehe i doing the smae unit rn.

if a=1 (which it does do ac factoring)

you need two numbers that multiply to -30 and add to 1. those numbers  are 5 and -6.

substitute 1x for -5x + 6x.

group the numbers into pairs and find their gcf's

x(x-5)    6(x-5)

since the parenthesis r the same yo only need one. Now you need to put x and 6 in a parenthesis.

FINAL: (x-5)(x+6) hope this helps

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3 years ago
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Step-by-step explanation:

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Elise drew p pictures. Nora drew 70 fewer pictures than Elise. Write an expression that shows how many pictures Nora drew
Naily [24]

Answer:

p - 70

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Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
-4(2-5b)=132<br> whats b?
Xelga [282]

Answer:

b = 7

Step-by-step explanation:

- 4(2 - 5b) = 132

- 4 × 2 - 4 × (- 5b) = 132

-8 + 20b = 132

20b = 132 + 8

20b = 140

b = 140/20

b = 7

Thus, The value of b is 7

<u>-TheUnknown</u><u>S</u><u>cientist</u>

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