When it comes to graphing, Desmos is a lifesaver!
I believe its B
Answer:
x=-4 x=2
Step-by-step explanation:
y = x^2 + 2x - 8
Set equal to zero
0 = x^2 + 2x - 8
Factor
What two numbers multiply to -8 and add to 2
4 * -2 = -8
4+-2 = 2
0=(x+4) ( x-2)
Using the zero product property
x+4 =0 x-2 =0
x=-4 x=2
Answer:
Exponential
Step-by-step explanation:
Since the x is to the power of 4, a small increase in x is amplified when it becomes the output of y.
Edit: Here is a screenshot of the graph
Answer:
16
Step-by-step explanation:
Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:
![64^\frac{2}{3} = \sqrt[3]{64^{2}}\\](https://tex.z-dn.net/?f=64%5E%5Cfrac%7B2%7D%7B3%7D%20%3D%20%5Csqrt%5B3%5D%7B64%5E%7B2%7D%7D%5C%5C)
As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.
![64^\frac{x}{y} = \sqrt[y]{64^{x}}](https://tex.z-dn.net/?f=64%5E%5Cfrac%7Bx%7D%7By%7D%20%3D%20%5Csqrt%5By%5D%7B64%5E%7Bx%7D%7D)
Both the original problem (64^2/3) and the converted formula can be put into a calculator.
<u>Simplify (if you want to)</u>
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64 to the power of 2/3 is 16.
Answer:
NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height
Step-by-step explanation:
Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero
Velocity is the change in distance with respect to time.
V = {d(h(t)}/dt = -8π/7sin(πt/7)
At maximum height, -8π/7sin(πt/7) = 0
-Sin(πt/7) = 0
sin(πt/7) = 0
Taking the arcsin of both sides
arcsin(sin(πt/7)) = arcsin0
πt/7 = 0
t = 0
This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height