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RoseWind [281]
3 years ago
13

HELP (I WILL GIVE 30 POINTS)

Mathematics
2 answers:
In-s [12.5K]3 years ago
6 0

I think is (A)

> x = (8 - 2f^-1(x))²

=> x^(½) = 8 - 2f^-1(x).

=> -2f^-1(x) = 8 - √x

Therefore:

f^-1(x) = (8 - √x)/2

Hope this help

pav-90 [236]3 years ago
3 0

Answer:

4 ± 1/2sqrt(x) = y

This is not a function

Step-by-step explanation:

f(x) = (8-2x)^2

y = (8-2x)^2

To find the inverse function, exchange x and y and then solve for y

x = (8-2y)^2

Take the square root of each side

±sqrt(x) = 8-2y

Subtract 8 from each side

-8±sqrt(x) = 8-8-2y

-8±sqrt(x) = -2y

Divide by -2

-8/-2±  1/2sqrt(x) = -2/-2y

4 ± 1/2sqrt(x) = y

This is not a function

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Cherie is jogging around a circular track. She
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Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
3 years ago
In ΔHIJ, the measure of ∠J=90°, HI = 88 feet, and IJ = 62 feet. Find the measure of ∠I to the nearest tenth of a degree.
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Answer:

Step-by-step explanation:

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HELP IF RIGHT I WILL MARK BRAINLIEST!!!! TRUST
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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