I think is (A)
> x = (8 - 2f^-1(x))²
=> x^(½) = 8 - 2f^-1(x).
=> -2f^-1(x) = 8 - √x
Therefore:
f^-1(x) = (8 - √x)/2
Hope this help
Answer:
4 ± 1/2sqrt(x) = y
This is not a function
Step-by-step explanation:
f(x) = (8-2x)^2
y = (8-2x)^2
To find the inverse function, exchange x and y and then solve for y
x = (8-2y)^2
Take the square root of each side
±sqrt(x) = 8-2y
Subtract 8 from each side
-8±sqrt(x) = 8-8-2y
-8±sqrt(x) = -2y
Divide by -2
-8/-2± 1/2sqrt(x) = -2/-2y
− 17/4 or −4.25
hope it helps
x=5
7x-10=25
+10 +10
7x=35
divide by 7 both sides
X = 2Y = 8
X is 2 because half of 4 is 2 and Y is 8 because double of 4 is 8.