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2 years ago

• Write an expression that is equivalent to 3(7 + x). 3(7+ x) =

Mathematics

1 answer:

Darya [45]2 years ago

6 0

Step-by-step explanation:

3(7 + x) = 3×7 + 3x = 21 + 3x

remember, when you multiply two expressions, you need to multiply every term of the first expression with every term of the second expression, and then add all partial results (by considering the individual signs, of course).

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What is the value of x? 3x−8=8x+4/2 Enter your answer in the box.

bekas [8.4K]

Answer:

x = -2

Step-by-step explanation:

3x -8 =8x +4/2

3x -8 =8x +2

3x -3x -8 = 8x -3x +2 (subtract 3x both sides )

-8 = 5x +2

-8-2 =5x+2 -2 (subtract 2 both sides )

-10 =5x

-10/5 = 5x/5 (divide 5 both sides)

-2 = x

3 0

3 years ago

1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav

OLga [1]

Answer:

(1) y=C, $C\neq0$

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant, $C \neq 0$ , has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

$\Rightarrow x=C$ , where $C\neq0$ .

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0

4 years ago

A plane flew 525 miles in 1.75 hours. Find the average speed of the plane.

ale4655 [162]

We are trying to find the average speed of the plane, which is mph, or $\dfrac{\textrm{miles}}{\textrm{hour}}$ . Using proportions, we can find the average speed of the plane in mph:

$\dfrac{525 \,\, \textrm{miles}}{1.75 \,\,\textrm{hours}} = \dfrac{x \,\, \textrm{miles}}{1 \,\,\textrm{hour}}$

Use the information from the problem to create a proportion. Remember that we are looking for mph, so we will call that $x$ .

$\dfrac{525}{1.75} \,\textrm{miles} = x \,\textrm{miles}$

Multiply the entire equation by $1 \,\textrm{hour}$

$\dfrac{525}{1.75} = 300 = x$

Divide both sides of the equation by $1 \,\textrm{mile}$ to clear both sides of the mile unit

The average speed of the plane is 300 mph.

6 0

4 years ago

Negation of all owls fly?

Reptile [31]

Looking at this in terms of sets, let's call O the set of all owls, and F the set of all things that can fly. What this original statement is saying every animal that's a member of the set of all owls is also a member of the set of all things that can fly, or in other words, O⊂F (O is a subset of F). Negating this tells us that, while there's at least one element of O that also belongs to F, O is not contained entirely in F (O⊆F, in notation), so a good negation or our original statement might be:

Not all owls can fly.

8 0

3 years ago

Read 2 more answers

Marco can finish a jigsaw puzzle in 3 hours. Working together with Cliff, it takes them 1 hour. How

vovikov84 [41]

Macro can finish the puzzle in 3 hours. We can say that her speed for working is 1/3 or 1/3 puzzle per hour.

Now if they work together, this turns into 1 puzzle per hour.

That must mean that Cliff would be doing the other 2/3 of the puzzle while Macro does his 1/3 in that hour. If Cliff has a speed of doing them 2/3 per hour. Then it would take 1 and a half hour to finish 1 whole puzzle.

3 0

3 years ago