Find an equation for the line that passes throughthe points (1,-1) and (-3,5)

Mathematics

2 answers:

Sladkaya [172]3 years ago

5 0

y = -1.5(x) + 0.5

points: (1,-1) and (-3,5)

slope:

⇒ (y2-y1)/(x2-x1)

⇒ (5-(-1))/(-3-1)

⇒ 6/-4

⇒ -1.5

equation:

⇒ y -(-1) = -1.5(x-1)

⇒ y + 1 = -1.5(x) + 1.5

⇒ y = -1.5(x) + 0.5

Tju [1.3M]3 years ago

4 0

U can pick either point to finish

y - 1 = 2(x-1)
y= 2x-2 +1
y = 2x-1

or

y-5 = 2(x-3)
y = 2x-6+5
y = 2x-1

You might be interested in

6x - 8; 2(3x - 5) are they equivalent?

ycow [4]

Nope.........................................................

7 0

3 years ago

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have