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saw5 [17]
3 years ago
11

56 projects 5:9 ratio divide

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0
The answer is 4:4 it takes 4 of each





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Elsa wants to draw a second rectangle that is the same length but is 3 times as wide. What is the width of Elsa's second rectang
Art [367]

Answer:

Whatever the length and width of the first triangle are take them and multiply by three. Place them in their respective sides of the new rectangle. The answer should be 9.

Step-by-step explanation:

3 0
3 years ago
Help me with this problem
siniylev [52]
The answer of your problem is C. Because 25 and 100 are related integers.
5 0
3 years ago
Read 2 more answers
Find mean, median, mode for the following. The following table of grouped data represents the weight (in pounds) of 100 Computer
ExtremeBDS [4]

Answer:

<em>A.(for weight in pounds)</em>

3, 4, 5, 6, 7

Median: 5

Mode: There are no mode in the following data set.

Mean: 3 + 4 + 5 + 6 + 7 = 25/5 = 25

<em>B.(for number of computers)</em>

4, 8, 18, 25, 45

Median: 18

Mode: There are no mode in the following data set.

Mean: 4 + 8 + 18 + 25 + 45 = 100/5 = 20

~hope this helps~

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5 0
3 years ago
What is the measure of angle GXD?​
s2008m [1.1K]

Answer:

75 = GXD

Step-by-step explanation:

We know that CXE is a straight line

A straight line is 180 degrees

CXE = CXG + GXD +DXE

Substituting what we know

180 = 85+ GXD + 20

Combine like terms

180 = 105+GXD

Subtract 105 from each side

180-105 = 105-105 +GXD

75 = GXD

7 0
3 years ago
Suppose a Hispanic Heritage festival is held in an area measuring 2,494 square yards. If the length of the festival is 58 yards,
Kaylis [27]

Answer: 43 yards.

Step-by-step explanation:

Let the shape of the area occupied for festival be rectangle.

and area of rectangle = length x width

Given: Area of the festival= 2,494 square yards.

Length of the festival=  58 yards

Then width = (Area )÷ (length)

=  (2494)÷58  yards

= 43 yards

hence, the  width of the festival = 43 yards.

4 0
3 years ago
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