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kotegsom [21]
3 years ago
8

How much of the 8% solution should we use to make 100g of a 3% solution?

Mathematics
2 answers:
sp2606 [1]3 years ago
8 0
Suppose x grams of 8% solution should be mixed to make 100 g of 3% solution.
here we shall have:
the amount of 3% solution in the 100 g will be:
3/100*100=3 grams
the the equation will be, 8% of what quantity becomes 3g?
(8/100)*x=3
hence solving for x we shall have:
0.08x=3
x=3/0.08
x= 37.8 grams
The implication of this is that, when you have 37.5 grams of 8% solution, that will contain 3  of pure chemical and hence when you add more solvent on top of 37.5 g until you reach 100g, that will be 3% solution.
gizmo_the_mogwai [7]3 years ago
8 0

Answer: 37.5 gram

Step-by-step explanation:

Since, by the dilution equation,

M_1\times V_1 = M_2\times V_2

Where, M_1 and V_1 are the molarity and volume of the concentrated stock solution and M_2 and V_2 are the molarity and volume of the diluted solution we want to make.

Here, M_1 = 8\% = 0.08,

M_2 = 3\% = 0.03,

V_2 = 100\text{ gram}

And, V_1 = ?,

0.08\times V_1 = 100\times 0.03

0.08\times V_1 = 3

8\times V_1 = 300

V_1 = 37.5\text{ gram}


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