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2 years ago

2,5,8,... Find the 41st term.

Mathematics

1 answer:

Snezhnost [94]2 years ago

8 0

Answer:

Step-by-step explanation:

hello :

this is the arithmetic -sequence because : 8-5=5-5=3 (comon dif)

An =A1+(n-1)r calculate......... (A1=2 and r=3 and n=41) continu...

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Minchanka [31]

The quadratic formula is $y = ax^{2} +bx+ c$

$x^2-8x + 16 = 0\\(x-4)(x-4) = 0$

So the solution for k is 16.

Hope that helps!

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2 years ago

A bicycle cover a distance of hundred metre in 5 second calculate the speed of the bicycle

Debora [2.8K]

Answer:

The formula of speed :-

Speed = Distance/Time

Given distance = 10m

Time = 40s

Speed = 10/40

= 1/4

= 0.25m/s

Step-by-step explanation:

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3 years ago

The sector of a circle has an area of 104pi/9 square inches and a central angle with measure 65 degrees. What is the radious of

kompoz [17]

Answer: b. 8

Step-by-step explanation: I don’t have work

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3 years ago

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

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3 years ago

Todd has $124 in his checking account. He wrote two checks for $13.96 and $21.67 and transferred $14 into his checking from

dangina [55]

Answer: $74.37

Step-by-step explanation:

7 0

3 years ago