The relationship between Sabir and calories he burns can be modeled using a linear function given by:
y=ax+b
where
a=slope
b=y-intercept
from the graph, the slope will be given as follows:
taking points (3,15) and (12,60)
a=(60-15)/(12-3)=5 calories/minute
thus using the slope and a point (3,15) the equation will be:
a(x1-x)=(y1-y)
plugging the values we obtain:
5(x-3)=y-15
5x-15=y-15
thus
y=5x
thus the equation is:
y=5x
Answer:
x=4
Step-by-step explanation:
√x+12=x
x+12=x2(Square both sides)
x+12=x2
x+12−x2=x2−x2(Subtract x^2 from both sides)
−x2+x+12=0
(−x−3)(x−4)=0(Factor left side of equation)
−x−3=0 or x−4=0(Set factors equal to 0)
x=−3 or x=4
x=−3(Doesn't work in original equation)
x=√x+12
I'm assuming you want an equation with a slope of -5 that also passes through the point (1, -7).
An equation that fits this is
Hope this helps!
In x^3=64, X is equal to 4
